\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
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\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{l15\_qmax\_1 (TMQbt12B4hMcspC1BoUTYKonBFRUCuHHpa9)}
\maketitle
Let $ r1\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k10\_xtuple\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k6\_domain\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k2\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k5\_numbers : {\iota}$ be given.
Let $ k1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k12\_prob\_1 : {\iota}$ be given.
Let $ k1\_numbers : {\iota}$ be given.
Let $ k1\_domain\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}}$ be given.
Let $ k6\_numbers : {\iota}$ be given.
Let $ c3\_\_qmax\_1 : {\iota}$ be given.
Let $ k1\_qmax\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_tarski : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ v1\_xboole\_0 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ v1\_funct\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ c2\_\_qmax\_1 : {\iota}$ be given.
Let $ v1\_funct\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{\unicdcdadad} X1 .  {{({{{r1\_tarski}~{({{k1\_tarski}~{X0}})}}~{X1}})}{\unicdbdjded}{({{X0} \in {X1}})}}}}\label{hyp:ehddbdpfkhggngjgdhdgpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  ((\preoh v1\_xboole\_0~X0){\unicdcdcdhd}(m1\_subset\_1~X1~X0)){\unicdbdjdcd}\\
(k6\_domain\_1~X0~X1=k1\_tarski~X1)\end{array}
\label{hyp:chfgegfgggjgogjgehjgpgogpflggdpfegpgngbgjgogpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}(k10\_xtuple\_0~(k6\_domain\_1~(k2\_zfmisc\_1~(k2\_zfmisc\_1~k5\_numbers~\\
k5\_numbers)~(k1\_zfmisc\_1~(k2\_zfmisc\_1~k12\_prob\_1~k1\_numbers)))~\\
(k1\_domain\_1~(k2\_zfmisc\_1~k5\_numbers~k5\_numbers)~(k1\_zfmisc\_1~\\
(k2\_zfmisc\_1~k12\_prob\_1~k1\_numbers))~(k1\_domain\_1~k5\_numbers~\\
k5\_numbers~k6\_numbers~k6\_numbers)~c3\_\_qmax\_1))=k6\_domain\_1~\\
(k1\_zfmisc\_1~(k2\_zfmisc\_1~k12\_prob\_1~k1\_numbers))~c3\_\_qmax\_1){\unicdcdcdhd}\\
(c3\_\_qmax\_1 \in k1\_qmax\_1~k1\_numbers~k12\_prob\_1)\end{array}
\label{hyp:mgbdedpfbhngbgihpfbd}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {\preoh{{{v1\_xboole\_0}~{({{k1\_zfmisc\_1}~{X0}})}}}}}\label{hyp:ggdgbdpfdhfhcgdhfgehpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}(v1\_funct\_1~c2\_\_qmax\_1){\unicdcdcdhd}((v1\_funct\_2~c2\_\_qmax\_1~k12\_prob\_1~\\
k1\_numbers){\unicdcdcdhd}(m1\_subset\_1~c2\_\_qmax\_1~(k1\_zfmisc\_1~(k2\_zfmisc\_1~\\
k12\_prob\_1~k1\_numbers))))\end{array}
\label{hyp:egehpfdgcdpfpfbhngbgihpfbd}
\end{equation}
Assume the following.
\begin{equation}
{{c3\_\_qmax\_1}={c2\_\_qmax\_1}}\label{hyp:egfgpfdgddpfpfbhngbgihpfbd}
\end{equation}
\begin{theorem}\label{thm:mgbdfdpfbhngbgihpfbd}
$$\begin{array}{c}r1\_tarski~(k10\_xtuple\_0~(k6\_domain\_1~(k2\_zfmisc\_1~(k2\_zfmisc\_1~\\
k5\_numbers~k5\_numbers)~(k1\_zfmisc\_1~(k2\_zfmisc\_1~k12\_prob\_1~\\
k1\_numbers)))~(k1\_domain\_1~(k2\_zfmisc\_1~k5\_numbers~k5\_numbers)~\\
(k1\_zfmisc\_1~(k2\_zfmisc\_1~k12\_prob\_1~k1\_numbers))~(k1\_domain\_1~\\
k5\_numbers~k5\_numbers~k6\_numbers~k6\_numbers)~c3\_\_qmax\_1)))~(\\
k1\_qmax\_1~k1\_numbers~k12\_prob\_1)\end{array}$$
\end{theorem}
\end{document}
