\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{l24\_scmfsa\_1 (TMZvvJQ8rq2AmKCvCW5gpPHWpjNEzBiRLob)}
\maketitle
Let $ k1\_afinsq\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k7\_afinsq\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}$ be given.
Let $ k5\_numbers : {\iota}$ be given.
Let $ k4\_numbers : {\iota}$ be given.
Let $ k3\_finseq\_2 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ np\_\_3 : {\iota}$ be given.
Let $ v1\_relat\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v5\_ordinal1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v1\_funct\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v1\_finset\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k1\_funct\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k6\_numbers : {\iota}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  {\unicdcdadad} X3 .  ((v1\_relat\_1~X3){\unicdcdcdhd}\\
((v5\_ordinal1~X3){\unicdcdcdhd}((v1\_funct\_1~X3){\unicdcdcdhd}(v1\_finset\_1~X3)))){\unicdbdjdcd}((X3=\\
k7\_afinsq\_1~X0~X1~X2){\unicdbdjded}((k1\_afinsq\_1~X3=np\_\_3){\unicdcdcdhd}((k1\_funct\_1~X3~\\
k6\_numbers=X0){\unicdcdcdhd}((k1\_funct\_1~X3~np\_\_1=X1){\unicdcdcdhd}(k1\_funct\_1~X3~np\_\_2=\\
X2)))))\end{array}
\label{hyp:ehddjdpfbgggjgogdhbhpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  (v5\_ordinal1~(k7\_afinsq\_1~X0~\\
X1~X2)){\unicdcdcdhd}(v1\_finset\_1~(k7\_afinsq\_1~X0~X1~X2))\end{array}
\label{hyp:ggdgbdcdpfbgggjgogdhbhpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  (v1\_relat\_1~(k7\_afinsq\_1~X0~\\
X1~X2)){\unicdcdcdhd}(v1\_funct\_1~(k7\_afinsq\_1~X0~X1~X2))\end{array}
\label{hyp:ggdgbdadpfbgggjgogdhbhpfbd}
\end{equation}
\begin{theorem}\label{thm:mgcdedpfdhdgngggdhbgpfbd}
$$\begin{array}{c}k1\_afinsq\_1~(k7\_afinsq\_1~k5\_numbers~k4\_numbers~(k3\_finseq\_2~\\
k4\_numbers))=np\_\_3\end{array}$$
\end{theorem}
\end{document}
