\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{l27\_realset2 (TMamLWFwBD2FPRbhJjkYSoxcsn9D7y3Tzeu)}
\maketitle
Let $ v1\_funct\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k1\_realset2 : {\iota}$ be given.
Let $ v1\_funct\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Let $ k2\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ c4\_\_realset2 : {\iota}$ be given.
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}(v1\_funct\_1~k1\_realset2){\unicdcdcdhd}((v1\_funct\_2~k1\_realset2~(k2\_zfmisc\_1~\\
np\_\_2~np\_\_2)~np\_\_2){\unicdcdcdhd}(m1\_subset\_1~k1\_realset2~(k1\_zfmisc\_1~(k2\_zfmisc\_1~\\
(k2\_zfmisc\_1~np\_\_2~np\_\_2)~np\_\_2))))\end{array}
\label{hyp:egehpflgbdpfchfgbgmgdhfgehcd}
\end{equation}
Assume the following.
\begin{equation}
{{c4\_\_realset2}={np\_\_2}}\label{hyp:egfgpfdgedpfpfchfgbgmgdhfgehcd}
\end{equation}
\begin{theorem}\label{thm:mgcdhdpfchfgbgmgdhfgehcd}
$$\begin{array}{c}(v1\_funct\_1~k1\_realset2){\unicdcdcdhd}((v1\_funct\_2~k1\_realset2~(k2\_zfmisc\_1~\\
c4\_\_realset2~c4\_\_realset2)~c4\_\_realset2){\unicdcdcdhd}(m1\_subset\_1~k1\_realset2~\\
(k1\_zfmisc\_1~(k2\_zfmisc\_1~(k2\_zfmisc\_1~c4\_\_realset2~c4\_\_realset2)~\\
c4\_\_realset2))))\end{array}$$
\end{theorem}
\end{document}
