\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{l47\_arytm\_2 (TMWwrTmZxnJMTMBxe5m6UV7Dg7Kmu1pf6dy)}
\maketitle
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k5\_arytm\_3 : {\iota}$ be given.
Let $ k1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ r3\_arytm\_3 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
\begin{theorem}\label{thm:mgedhdpfbgchjhehngpfcd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k5\_arytm\_3){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~k5\_arytm\_3){\unicdbdjdcd}({\unicdcdadad} X2 .  ((X2 \in ReplSep~(toset~({\uniddcgcg} X3 : \iota .  \\
m1\_subset\_1~X3~(k1\_zfmisc\_1~k5\_arytm\_3)))~({\uniddcgcg} X3 : \iota .  {\unicdcdadad} X4 .  \\
(m1\_subset\_1~X4~k5\_arytm\_3){\unicdbdjdcd}((X4 \in X3){\unicdbdjdcd}(({\unicdcdadad} X5 .  (m1\_subset\_1~\\
X5~k5\_arytm\_3){\unicdbdjdcd}((r3\_arytm\_3~X5~X4){\unicdbdjdcd}(X5 \in X3))){\unicdcdcdhd}({\unicdcdaddd} X5 .  (m1\_subset\_1~\\
X5~k5\_arytm\_3){\unicdcdcdhd}((X5 \in X3){\unicdcdcdhd}(\preoh r3\_arytm\_3~X5~X4))))))~({\uniddcgcg} X3 : \iota .  \\
X3)){\unicdcdcdhd}((X0 \in X2){\unicdcdcdhd}(r3\_arytm\_3~X1~X0))){\unicdbdjdcd}(X1 \in X2)))\end{array}$$
\end{theorem}
\end{document}
