\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{l55\_scmyciel (TMFiQZaWcks49We224EMq5Hp7LtEzkQh4gT)}
\maketitle
Let $ v4\_scmyciel : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k6\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k5\_scmyciel : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k3\_tarski : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_scmyciel : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k2\_xboole\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_tarski : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_xboole\_0 : {\iota}$ be given.
Let $ k9\_bspace : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k2\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v4\_scmyciel~X0){\unicdbdjdcd}(X0=k2\_xboole\_0~(k2\_xboole\_0~(k1\_tarski~\\
k1\_xboole\_0)~(k9\_bspace~(k3\_tarski~X0)))~(k1\_scmyciel~X0))\end{array}
\label{hyp:ehcdhdpfdhdgngjhdgjgfgmg}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{\unicdcdadad} X1 .  {{({{\unicdcdadad} X2 .  {{({{X2} \in {X0}})}{\unicdbdjded}{({{X2} \in {X1}})}}})}{\unicdbdjdcd}{({{X0}={X1}})}}}}\label{hyp:ehbdpfehbgchdhlgjg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  \preoh (X1 \in k1\_scmyciel~X0){\unicdcdcdhd}({\unicdcdadad} X2 .  {\unicdcdadad} X3 .  \\
\preoh (X2{\unicdcdgdad}X3){\unicdcdcdhd}((X2 \in k3\_tarski~X0){\unicdcdcdhd}((X3 \in k3\_tarski~X0){\unicdcdcdhd}(X1=k2\_tarski~\\
X2~X3))))\end{array}
\label{hyp:ehbdbdpfdhdgngjhdgjgfgmg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v4\_scmyciel~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  {\unicdcdadad} X2 .  ((X1 \in k3\_tarski~\\
X0){\unicdcdcdhd}(X2 \in k3\_tarski~X0)){\unicdbdjdcd}((X1=X2){\unicdcdcdid}((k2\_tarski~X1~X2 \in k1\_scmyciel~\\
X0){\unicdbdjded}(\preoh k2\_tarski~X1~X2 \in k1\_scmyciel~(k6\_subset\_1~(k5\_scmyciel~\\
(k3\_tarski~X0))~(k1\_scmyciel~X0))))))\end{array}
\label{hyp:mgfdedpfdhdgngjhdgjgfgmg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v4\_scmyciel~X0){\unicdbdjdcd}(k3\_tarski~X0=k3\_tarski~(k6\_subset\_1~\\
(k5\_scmyciel~(k3\_tarski~X0))~(k1\_scmyciel~X0)))\end{array}
\label{hyp:mgfdddpfdhdgngjhdgjgfgmg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v4\_scmyciel~X0){\unicdbdjdcd}(v4\_scmyciel~(k6\_subset\_1~(k5\_scmyciel~\\
(k3\_tarski~X0))~(k1\_scmyciel~X0)))\end{array}
\label{hyp:mgfdcdpfdhdgngjhdgjgfgmg}
\end{equation}
\begin{theorem}\label{thm:mgfdfdpfdhdgngjhdgjgfgmg}
$$\begin{array}{c}{\unicdcdadad} X0 .  (v4\_scmyciel~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (v4\_scmyciel~X1){\unicdbdjdcd}((\\
X1=k6\_subset\_1~(k5\_scmyciel~(k3\_tarski~X0))~(k1\_scmyciel~X0)){\unicdbdjdcd}\\
(k6\_subset\_1~(k5\_scmyciel~(k3\_tarski~X1))~(k1\_scmyciel~X1)=X0)))\end{array}$$
\end{theorem}
\end{document}
