\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{l6\_topalg\_5 (TMKyztFfFD73RV954c6vajPmV1qP1bdZrMW)}
\maketitle
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k6\_numbers : {\iota}$ be given.
Let $ u1\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k5\_topmetr : {\iota}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ k17\_borsuk\_1 : {\iota}$ be given.
Let $ k19\_borsuk\_1 : {\iota}$ be given.
Let $ k18\_borsuk\_1 : {\iota}$ be given.
Assume the following.
\begin{equation}
{{k5\_topmetr}={k17\_borsuk\_1}}\label{hyp:chfgegfgggjgogjgehjgpgogpflgfdpfehpgahngfgehch}
\end{equation}
Assume the following.
\begin{equation}
{{{m1\_subset\_1}~{k19\_borsuk\_1}}~{({{u1\_struct\_0}~{k17\_borsuk\_1}})}}\label{hyp:egehpflgbdjdpfcgpgchdhfhlgpfbd}
\end{equation}
Assume the following.
\begin{equation}
{{{m1\_subset\_1}~{k18\_borsuk\_1}}~{({{u1\_struct\_0}~{k17\_borsuk\_1}})}}\label{hyp:egehpflgbdidpfcgpgchdhfhlgpfbd}
\end{equation}
Assume the following.
\begin{equation}
{{k19\_borsuk\_1}={np\_\_1}}\label{hyp:egbdfdpfcgpgchdhfhlgpfbd}
\end{equation}
Assume the following.
\begin{equation}
{{k18\_borsuk\_1}={k6\_numbers}}\label{hyp:egbdedpfcgpgchdhfhlgpfbd}
\end{equation}
\begin{theorem}\label{thm:mggdpfehpgahbgmghgpffd}
$$\begin{array}{c}(m1\_subset\_1~k6\_numbers~(u1\_struct\_0~k5\_topmetr)){\unicdcdcdhd}(m1\_subset\_1~\\
np\_\_1~(u1\_struct\_0~k5\_topmetr))\end{array}$$
\end{theorem}
\end{document}
