\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
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\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
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\begin{document}
\title{l93\_toprealb (TMJiBGgs2LGcGtxpiS3otF62soLH3tFy6Eo)}
\maketitle
Let $ k1\_relset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_numbers : {\iota}$ be given.
Let $ k1\_fcont\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k10\_real\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ k8\_real\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ k32\_sin\_cos : {\iota}$ be given.
Let $ k6\_numbers : {\iota}$ be given.
Let $ u1\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k3\_topmetr : {\iota}$ be given.
Let $ k2\_topalg\_2 : {\iota}$ be given.
Assume the following.
\begin{equation}
{{{u1\_struct\_0}~{k3\_topmetr}}={k1\_numbers}}\label{hyp:ehbdhdpfehpgahngfgehch}
\end{equation}
Assume the following.
\begin{equation}
{{k2\_topalg\_2}={k3\_topmetr}}\label{hyp:chfgegfgggjgogjgehjgpgogpflgcdpfehpgahbgmghgpfcd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}k1\_relset\_1~k1\_numbers~(k1\_fcont\_1~(k10\_real\_1~np\_\_1~(k8\_real\_1~\\
np\_\_2~k32\_sin\_cos))~k6\_numbers)=u1\_struct\_0~k2\_topalg\_2\end{array}
\label{hyp:mgididpfehpgahchfgbgmgcg}
\end{equation}
\begin{theorem}\label{thm:mgjdddpfehpgahchfgbgmgcg}
$$\begin{array}{c}k1\_relset\_1~k1\_numbers~(k1\_fcont\_1~(k10\_real\_1~np\_\_1~(k8\_real\_1~\\
np\_\_2~k32\_sin\_cos))~k6\_numbers)=k1\_numbers\end{array}$$
\end{theorem}
\end{document}
