\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t103\_relat\_1 (TMNay4qAGj3ii1ctiKdbwuRoL8pi8oPfyf8)}
\maketitle
Let $ v1\_relat\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k6\_relat\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k2\_xboole\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k2\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k3\_xboole\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k9\_xtuple\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  (k2\_zfmisc\_1~(k2\_xboole\_0~X0~\\
X1)~X2=k2\_xboole\_0~(k2\_zfmisc\_1~X0~X2)~(k2\_zfmisc\_1~X1~X2)){\unicdcdcdhd}(k2\_zfmisc\_1~\\
X2~(k2\_xboole\_0~X0~X1)=k2\_xboole\_0~(k2\_zfmisc\_1~X2~X0)~(k2\_zfmisc\_1~\\
X2~X1))\end{array}
\label{hyp:ehjdhdpfkhggngjgdhdgpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (v1\_relat\_1~X1){\unicdbdjdcd}(k6\_relat\_1~X0~X1=k3\_xboole\_0~\\
X1~(k2\_zfmisc\_1~(k9\_xtuple\_0~X1)~X0))\end{array}
\label{hyp:ehjdddpfchfgmgbgehpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  k3\_xboole\_0~X0~(k2\_xboole\_0~\\
X1~X2)=k2\_xboole\_0~(k3\_xboole\_0~X0~X1)~(k3\_xboole\_0~X0~X2)\end{array}
\label{hyp:ehcdddpfihcgpgpgmgfgpfbd}
\end{equation}
\begin{theorem}\label{thm:ehbdadddpfchfgmgbgehpfbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  (v1\_relat\_1~X2){\unicdbdjdcd}(k6\_relat\_1~\\
(k2\_xboole\_0~X0~X1)~X2=k2\_xboole\_0~(k6\_relat\_1~X0~X2)~(k6\_relat\_1~\\
X1~X2))\end{array}$$
\end{theorem}
\end{document}
