\documentclass{article}
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\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t104\_zfmisc\_1 (TMEtj1VoaUPmsV8uEn4sU3MHYXZCQh168Ni)}
\maketitle
Let $ r1\_xboole\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k2\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k3\_xboole\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k4\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  {\unicdcdadad} X3 .  {\unicdcdadad} X4 .  \preoh (X0 \in \\
k3\_xboole\_0~(k2\_zfmisc\_1~X1~X2)~(k2\_zfmisc\_1~X3~X4)){\unicdcdcdhd}({\unicdcdadad} X5 .  \\
{\unicdcdadad} X6 .  \preoh (X0=k4\_tarski~X5~X6){\unicdcdcdhd}((X5 \in k3\_xboole\_0~X1~X3){\unicdcdcdhd}(X6 \in \\
k3\_xboole\_0~X2~X4)))\end{array}
\label{hyp:ehidfdpfkhggngjgdhdgpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (\preoh (\preoh r1\_xboole\_0~X0~X1){\unicdcdcdhd}({\unicdcdadad} X2 .  \preoh X2 \in \\
k3\_xboole\_0~X0~X1)){\unicdcdcdhd}(\preoh ({\unicdcdaddd} X2 .  X2 \in k3\_xboole\_0~X0~X1){\unicdcdcdhd}(r1\_xboole\_0~\\
X0~X1))\end{array}
\label{hyp:ehedpfihcgpgpgmgfgpfad}
\end{equation}
\begin{theorem}\label{thm:ehbdadedpfkhggngjgdhdgpfbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  {\unicdcdadad} X3 .  ((r1\_xboole\_0~X0~\\
X1){\unicdcdcdid}(r1\_xboole\_0~X2~X3)){\unicdbdjdcd}(r1\_xboole\_0~(k2\_zfmisc\_1~X0~X2)~(k2\_zfmisc\_1~\\
X1~X3))\end{array}$$
\end{theorem}
\end{document}
