\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t10\_tdlat\_3 (TMU1bFNwHo1N4QuRP2wtVM1rTMpUqURSNvs)}
\maketitle
Let $ l1\_pre\_topc : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v1\_tdlat\_3 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v2\_tdlat\_3 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k9\_setfam\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ u1\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k2\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_xboole\_0 : {\iota}$ be given.
Let $ u1\_pre\_topc : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (l1\_pre\_topc~X0){\unicdbdjdcd}((v2\_tdlat\_3~X0){\unicdbdjded}(u1\_pre\_topc~X0=\\
k2\_tarski~k1\_xboole\_0~(u1\_struct\_0~X0)))\end{array}
\label{hyp:egcdpfehegmgbgehpfdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (l1\_pre\_topc~X0){\unicdbdjdcd}((v1\_tdlat\_3~X0){\unicdbdjded}(u1\_pre\_topc~X0=\\
k9\_setfam\_1~(u1\_struct\_0~X0)))\end{array}
\label{hyp:egbdpfehegmgbgehpfdd}
\end{equation}
\begin{theorem}\label{thm:ehbdadpfehegmgbgehpfdd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (l1\_pre\_topc~X0){\unicdbdjdcd}(((v1\_tdlat\_3~X0){\unicdcdcdhd}(v2\_tdlat\_3~X0)){\unicdbdjdcd}\\
(k9\_setfam\_1~(u1\_struct\_0~X0)=k2\_tarski~k1\_xboole\_0~(u1\_struct\_0~\\
X0)))\end{array}$$
\end{theorem}
\end{document}
