\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t136\_finseq\_2 (TMUbLKSBpc4gnv7PU1mVMEPbXNvg1cuy7u7)}
\maketitle
Let $ k9\_finseq\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k4\_finseq\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{\unicdcdadad} X1 .  {{({{{k9\_finseq\_1}~{X0}}={{k9\_finseq\_1}~{X1}}})}{\unicdbdjdcd}{({{X0}={X1}})}}}}\label{hyp:ehhdgdpfggjgogdhfgbhpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (X1 \in k4\_finseq\_2~np\_\_1~X0){\unicdbdjded}({\unicdcdaddd} X2 .  \\
(X2 \in X0){\unicdcdcdhd}(X1=k9\_finseq\_1~X2))\end{array}
\label{hyp:ehbdddfdpfggjgogdhfgbhpfcd}
\end{equation}
\begin{theorem}\label{thm:ehbdddgdpfggjgogdhfgbhpfcd}
$$\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (k9\_finseq\_1~X1 \in k4\_finseq\_2~np\_\_1~X0){\unicdbdjdcd}\\
(X1 \in X0)\end{array}$$
\end{theorem}
\end{document}
