\documentclass{article}
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\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
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\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
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\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t13\_nat\_lat (TMEwy7SeJW2yPYzNieCUJ1YBa3JDF7ecnHo)}
\maketitle
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ u1\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k10\_nat\_lat : {\iota}$ be given.
Let $ k1\_lattices : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}$ be given.
Let $ k5\_nat\_d : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k11\_nat\_lat : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  ((m1\_subset\_1~X0~(u1\_struct\_0~k10\_nat\_lat)){\unicdcdcdhd}\\
(m1\_subset\_1~X1~(u1\_struct\_0~k10\_nat\_lat))){\unicdbdjdcd}(k1\_lattices~k10\_nat\_lat~\\
X0~X1=k5\_nat\_d~X0~X1)\end{array}
\label{hyp:jgfgddpfogbgehpfmgbgeh}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~(u1\_struct\_0~k10\_nat\_lat)){\unicdbdjdcd}(k11\_nat\_lat~\\
X0=X0)\end{array}
\label{hyp:egbdbdpfogbgehpfmgbgeh}
\end{equation}
\begin{theorem}\label{thm:ehbdddpfogbgehpfmgbgeh}
$$\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~(u1\_struct\_0~k10\_nat\_lat)){\unicdbdjdcd}({\unicdcdadad} X1 .  \\
(m1\_subset\_1~X1~(u1\_struct\_0~k10\_nat\_lat)){\unicdbdjdcd}(k1\_lattices~k10\_nat\_lat~\\
X0~X1=k5\_nat\_d~(k11\_nat\_lat~X0)~(k11\_nat\_lat~X1)))\end{array}$$
\end{theorem}
\end{document}
