\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
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\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
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\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t13\_qmax\_1 (TMPPzmkiyCyZsMjbcqtTwdrETjJEh5CCfqE)}
\maketitle
Let $ v2\_qmax\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ l1\_qmax\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k5\_qmax\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k8\_eqrel\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k9\_qmax\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k8\_qmax\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v2\_qmax\_1~X0){\unicdcdcdhd}(l1\_qmax\_1~X0)){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~(k1\_zfmisc\_1~(k5\_qmax\_1~X0))){\unicdbdjdcd}({\unicdcdadad} X2 .  (m1\_subset\_1~X2~\\
(k1\_zfmisc\_1~(k5\_qmax\_1~X0))){\unicdbdjdcd}(((X1 \in k8\_eqrel\_1~(k5\_qmax\_1~X0)~\\
(k9\_qmax\_1~X0)){\unicdcdcdhd}(X2 \in k8\_eqrel\_1~(k5\_qmax\_1~X0)~(k9\_qmax\_1~X0))){\unicdbdjdcd}\\
({\unicdcdadad} X3 .  (m1\_subset\_1~X3~(k5\_qmax\_1~X0)){\unicdbdjdcd}({\unicdcdadad} X4 .  (m1\_subset\_1~\\
X4~(k5\_qmax\_1~X0)){\unicdbdjdcd}(((X3 \in X1){\unicdcdcdhd}((X4 \in X1){\unicdcdcdhd}(k8\_qmax\_1~X0~X3 \in X2))){\unicdbdjdcd}\\
(k8\_qmax\_1~X0~X4 \in X2)))))))\end{array}
\label{hyp:ehbdcdpfbhngbgihpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (((v2\_qmax\_1~X0){\unicdcdcdhd}(l1\_qmax\_1~X0)){\unicdcdcdhd}(m1\_subset\_1~\\
X1~(k5\_qmax\_1~X0))){\unicdbdjdcd}(k8\_qmax\_1~X0~(k8\_qmax\_1~X0~X1)=X1)\end{array}
\label{hyp:jgogghpgmgfhehjgghfgogfgdhdhpflgidpfbhngbgihpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (((v2\_qmax\_1~X0){\unicdcdcdhd}(l1\_qmax\_1~X0)){\unicdcdcdhd}(m1\_subset\_1~\\
X1~(k5\_qmax\_1~X0))){\unicdbdjdcd}(m1\_subset\_1~(k8\_qmax\_1~X0~X1)~(k5\_qmax\_1~\\
X0))\end{array}
\label{hyp:egehpflgidpfbhngbgihpfbd}
\end{equation}
\begin{theorem}\label{thm:ehbdddpfbhngbgihpfbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  ((v2\_qmax\_1~X0){\unicdcdcdhd}(l1\_qmax\_1~X0)){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~(k1\_zfmisc\_1~(k5\_qmax\_1~X0))){\unicdbdjdcd}({\unicdcdadad} X2 .  (m1\_subset\_1~X2~\\
(k1\_zfmisc\_1~(k5\_qmax\_1~X0))){\unicdbdjdcd}(((X1 \in k8\_eqrel\_1~(k5\_qmax\_1~X0)~\\
(k9\_qmax\_1~X0)){\unicdcdcdhd}(X2 \in k8\_eqrel\_1~(k5\_qmax\_1~X0)~(k9\_qmax\_1~X0))){\unicdbdjdcd}\\
({\unicdcdadad} X3 .  (m1\_subset\_1~X3~(k5\_qmax\_1~X0)){\unicdbdjdcd}({\unicdcdadad} X4 .  (m1\_subset\_1~\\
X4~(k5\_qmax\_1~X0)){\unicdbdjdcd}(((k8\_qmax\_1~X0~X3 \in X2){\unicdcdcdhd}((k8\_qmax\_1~X0~X4 \in X2){\unicdcdcdhd}\\
(X3 \in X1))){\unicdbdjdcd}(X4 \in X1)))))))\end{array}$$
\end{theorem}
\end{document}
