\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t14\_armstrng (TMHLfkHKuaQsPdm6Ywnr6a4jJREHZiYG5XG)}
\maketitle
Let $ k7\_armstrng : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k4\_armstrng : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k4\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ r3\_armstrng : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  k7\_armstrng~X0=ReplSep2~(toset~({\uniddcgcg} X1 : \iota .  m1\_subset\_1~\\
X1~(k4\_armstrng~X0)))~({\uniddcgcg} X1 : \iota .  toset~({\uniddcgcg} X2 : \iota .  m1\_subset\_1~\\
X2~(k4\_armstrng~X0)))~({\uniddcgcg} X1 : \iota .  {\uniddcgcg} X2 : \iota .  r3\_armstrng~X0~\\
X2~X1)~({\uniddcgcg} X1 : \iota .  {\uniddcgcg} X2 : \iota .  k4\_tarski~X1~X2)\end{array}
\label{hyp:egbdadpfbgchngdhehchoghg}
\end{equation}
\begin{theorem}\label{thm:ehbdedpfbgchngdhehchoghg}
$$\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (X1 \in k7\_armstrng~X0){\unicdbdjded}({\unicdcdaddd} X2 .  (m1\_subset\_1~\\
X2~(k4\_armstrng~X0)){\unicdcdcdhd}({\unicdcdaddd} X3 .  (m1\_subset\_1~X3~(k4\_armstrng~\\
X0)){\unicdcdcdhd}((X1=k4\_tarski~X2~X3){\unicdcdcdhd}(r3\_armstrng~X0~X3~X2))))\end{array}$$
\end{theorem}
\end{document}
