\documentclass{article}
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\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
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\begin{document}
\title{t14\_zf\_lang1 (TMRrhftE8atDQ9TtBnA1ayXqwb6n4nrxog4)}
\maketitle
Let $ v1\_zf\_lang : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ m2\_finseq\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k5\_numbers : {\iota}$ be given.
Let $ m2\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Let $ k1\_zf\_lang : {\iota}$ be given.
Let $ k14\_zf\_lang : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}$ be given.
Let $ k23\_zf\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k8\_zf\_lang : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k24\_zf\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ v6\_zf\_lang : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}({\unicdcdadad} X1 .  \\
(m2\_subset\_1~X1~k5\_numbers~k1\_zf\_lang){\unicdbdjdcd}((k23\_zf\_lang~(k8\_zf\_lang~\\
X1~X0)=X1){\unicdcdcdhd}(k24\_zf\_lang~(k8\_zf\_lang~X1~X0)=X0)))\end{array}
\label{hyp:ehidpfkhggpfmgbgoghgbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}({\unicdcdadad} X1 .  \\
(m2\_subset\_1~X1~k5\_numbers~k1\_zf\_lang){\unicdbdjdcd}({\unicdcdadad} X2 .  (m2\_subset\_1~\\
X2~k5\_numbers~k1\_zf\_lang){\unicdbdjdcd}((v6\_zf\_lang~(k14\_zf\_lang~X1~X2~X0)){\unicdcdcdhd}\\
((k23\_zf\_lang~(k14\_zf\_lang~X1~X2~X0)=X1){\unicdcdcdhd}(k24\_zf\_lang~(k14\_zf\_lang~\\
X1~X2~X0)=k8\_zf\_lang~X2~X0)))))\end{array}
\label{hyp:ehbdbdpfkhggpfmgbgoghgbd}
\end{equation}
\begin{theorem}\label{thm:ehbdedpfkhggpfmgbgoghgbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}({\unicdcdadad} X1 .  \\
((v1\_zf\_lang~X1){\unicdcdcdhd}(m2\_finseq\_1~X1~k5\_numbers)){\unicdbdjdcd}({\unicdcdadad} X2 .  (\\
m2\_subset\_1~X2~k5\_numbers~k1\_zf\_lang){\unicdbdjdcd}({\unicdcdadad} X3 .  (m2\_subset\_1~\\
X3~k5\_numbers~k1\_zf\_lang){\unicdbdjdcd}({\unicdcdadad} X4 .  (m2\_subset\_1~X4~k5\_numbers~\\
k1\_zf\_lang){\unicdbdjdcd}({\unicdcdadad} X5 .  (m2\_subset\_1~X5~k5\_numbers~k1\_zf\_lang){\unicdbdjdcd}\\
((k14\_zf\_lang~X2~X3~X0=k14\_zf\_lang~X4~X5~X1){\unicdbdjdcd}((X2=X4){\unicdcdcdhd}((X3=X5){\unicdcdcdhd}\\
(X0=X1)))))))))\end{array}$$
\end{theorem}
\end{document}
