\documentclass{article}
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\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
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\newcommand\unicdbdjded{\Leftrightarrow}
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\begin{document}
\title{t16\_cqc\_the3 (TMQYnqVjZtAqf4rsWZ4kKoXuMqZ8qY6CFAu)}
\maketitle
Let $ m1\_qc\_lang1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ r3\_cqc\_the3 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k4\_cqc\_the1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k3\_cqc\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ r2\_cqc\_the3 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Let $ k1\_subset\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_qc\_lang1~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~X1~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}((r3\_cqc\_the3~X0~X1){\unicdbdjded}(r2\_cqc\_the3~X0~(k1\_subset\_1~\\
(k3\_cqc\_lang~X0))~X1)))\end{array}
\label{hyp:ehbdfdpfdgbhdgpfehigfgdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_qc\_lang1~X0){\unicdbdjdcd}(r2\_cqc\_the3~X0~(k1\_subset\_1~(k3\_cqc\_lang~\\
X0))~(k4\_cqc\_the1~X0))\end{array}
\label{hyp:ehbdedpfdgbhdgpfehigfgdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_qc\_lang1~X0){\unicdbdjdcd}(m1\_subset\_1~(k4\_cqc\_the1~X0)~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0)))\end{array}
\label{hyp:egehpflgedpfdgbhdgpfehigfgbd}
\end{equation}
\begin{theorem}\label{thm:ehbdgdpfdgbhdgpfehigfgdd}
${{\unicdcdadad} X0 .  {{({{m1\_qc\_lang1}~{X0}})}{\unicdbdjdcd}{({{{r3\_cqc\_the3}~{X0}}~{({{k4\_cqc\_the1}~{X0}})}})}}}$.
\end{theorem}
\end{document}
