\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
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\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
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\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t17\_bcialg\_5 (TMKpvEv4EzzSmoWjDobDCQUhGtFiESTDpAA)}
\maketitle
Let $ m2\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Let $ k1\_numbers : {\iota}$ be given.
Let $ k5\_numbers : {\iota}$ be given.
Let $ v8\_bcialg\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ m1\_bcialg\_5 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}}}$ be given.
Let $ k2\_nat\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m2\_subset\_1~X0~k1\_numbers~k5\_numbers){\unicdbdjdcd}({\unicdcdadad} X1 .  \\
(m2\_subset\_1~X1~k1\_numbers~k5\_numbers){\unicdbdjdcd}({\unicdcdadad} X2 .  (m2\_subset\_1~\\
X2~k1\_numbers~k5\_numbers){\unicdbdjdcd}({\unicdcdadad} X3 .  (m2\_subset\_1~X3~k1\_numbers~\\
k5\_numbers){\unicdbdjdcd}({\unicdcdadad} X4 .  (m1\_bcialg\_5~X4~X0~X1~X2~X3){\unicdbdjdcd}({\unicdcdadad} X5 .  \\
(m2\_subset\_1~X5~k1\_numbers~k5\_numbers){\unicdbdjdcd}(m1\_bcialg\_5~X4~(k2\_nat\_1~\\
X0~X5)~X1~X2~(k2\_nat\_1~X3~X5)))))))\end{array}
\label{hyp:ehbdedpfcgdgjgbgmghgpffd}
\end{equation}
\begin{theorem}\label{thm:ehbdhdpfcgdgjgbgmghgpffd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (m2\_subset\_1~X0~k1\_numbers~k5\_numbers){\unicdbdjdcd}({\unicdcdadad} X1 .  \\
(m2\_subset\_1~X1~k1\_numbers~k5\_numbers){\unicdbdjdcd}({\unicdcdadad} X2 .  (m2\_subset\_1~\\
X2~k1\_numbers~k5\_numbers){\unicdbdjdcd}({\unicdcdadad} X3 .  (m2\_subset\_1~X3~k1\_numbers~\\
k5\_numbers){\unicdbdjdcd}({\unicdcdadad} X4 .  ((v8\_bcialg\_1~X4){\unicdcdcdhd}(m1\_bcialg\_5~X4~X0~\\
X1~X2~X3)){\unicdbdjdcd}({\unicdcdadad} X5 .  (m2\_subset\_1~X5~k1\_numbers~k5\_numbers){\unicdbdjdcd}\\
((v8\_bcialg\_1~X4){\unicdcdcdhd}(m1\_bcialg\_5~X4~(k2\_nat\_1~X0~X5)~X1~X2~(k2\_nat\_1~\\
X3~X5))))))))\end{array}$$
\end{theorem}
\end{document}
