\documentclass{article}
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\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
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\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
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\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t17\_euclid\_3 (TMR6DgW2V63tpZX5LDy6N3mgUDqfnMQmP2u)}
\maketitle
Let $ k2\_euclid\_3 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k4\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k15\_euclid : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ k5\_complex1 : {\iota}$ be given.
Let $ v1\_xcmplx\_0 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k1\_euclid\_3 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k2\_numbers : {\iota}$ be given.
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{({{v1\_xcmplx\_0}~{X0}})}{\unicdbdjdcd}{({{{k2\_euclid\_3}~{({{k1\_euclid\_3}~{X0}})}}={X0}})}}}\label{hyp:ehbdpffgfhdgmgjgegpfdd}
\end{equation}
Assume the following.
\begin{equation}
{{{k1\_euclid\_3}~{k5\_complex1}}={{k4\_struct\_0}~{({{k15\_euclid}~{np\_\_2}})}}}\label{hyp:ehbdgdpffgfhdgmgjgegpfdd}
\end{equation}
Assume the following.
\begin{equation}
{{{m1\_subset\_1}~{k5\_complex1}}~{k2\_numbers}}\label{hyp:egehpflgfdpfdgpgngahmgfgihbd}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{({{{m1\_subset\_1}~{X0}}~{k2\_numbers}})}{\unicdbdjdcd}{({{v1\_xcmplx\_0}~{X0}})}}}\label{hyp:dgdgddpfihdgngahmgihpfad}
\end{equation}
\begin{theorem}\label{thm:ehbdhdpffgfhdgmgjgegpfdd}
${{{k2\_euclid\_3}~{({{k4\_struct\_0}~{({{k15\_euclid}~{np\_\_2}})}})}}={k5\_complex1}}$.
\end{theorem}
\end{document}
