\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t18\_euler\_1 (TMadNnQEgFz6i5aLnxVcBNNcJwuQAfCQ5CU)}
\maketitle
Let $ k1\_euler\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ k5\_card\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_tarski : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
{{{k1\_euler\_1}~{np\_\_1}}={np\_\_1}}\label{hyp:ehbdhdpffgfhmgfgchpfbd}
\end{equation}
Assume the following.
\begin{equation}
{{{k5\_card\_1}~{({{k1\_tarski}~{np\_\_1}})}}={{k1\_euler\_1}~{np\_\_2}}}\label{hyp:mgcdedpffgfhmgfgchpfbd}
\end{equation}
Assume the following.
\begin{equation}
{{{k5\_card\_1}~{({{k1\_tarski}~{np\_\_1}})}}={{k1\_euler\_1}~{np\_\_1}}}\label{hyp:mgcdbdpffgfhmgfgchpfbd}
\end{equation}
\begin{theorem}\label{thm:ehbdidpffgfhmgfgchpfbd}
${{{k1\_euler\_1}~{np\_\_2}}={np\_\_1}}$.
\end{theorem}
\end{document}
