\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t18\_scmyciel (TMaqvk3dv6d9MXpxaYYzmc5o7Qqvs2JPVH1)}
\maketitle
Let $ k3\_tarski : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_xboole\_0 : {\iota}$ be given.
Let $ k1\_tarski : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ r1\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{{r1\_tarski}~{X0}}~{({{k1\_zfmisc\_1}~{({{k3\_tarski}~{X0}})}})}}}\label{hyp:ehidcdpfkhggngjgdhdgpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (r1\_tarski~X0~(k1\_tarski~X1)){\unicdbdjded}((X0=k1\_xboole\_0){\unicdcdcdid}\\
(X0=k1\_tarski~X1))\end{array}
\label{hyp:ehddddpfkhggngjgdhdgpfbd}
\end{equation}
Assume the following.
\begin{equation}
{{{k1\_zfmisc\_1}~{k1\_xboole\_0}}={{k1\_tarski}~{k1\_xboole\_0}}}\label{hyp:ehbdpfkhggngjgdhdgpfbd}
\end{equation}
\begin{theorem}\label{thm:ehbdidpfdhdgngjhdgjgfgmg}
$$\begin{array}{c}{\unicdcdadad} X0 .  \preoh (k3\_tarski~X0=k1\_xboole\_0){\unicdcdcdhd}((X0{\unicdcdgdad}k1\_xboole\_0){\unicdcdcdhd}\\
(X0{\unicdcdgdad}k1\_tarski~k1\_xboole\_0))\end{array}$$
\end{theorem}
\end{document}
