\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t1\_glib\_000 (TMZsn5usA3Pq8E38ite9p96bBoZS52TNewN)}
\maketitle
Let $ k1\_glib\_000 : {\iota}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ k2\_glib\_000 : {\iota}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ k3\_glib\_000 : {\iota}$ be given.
Let $ np\_\_3 : {\iota}$ be given.
Let $ k4\_glib\_000 : {\iota}$ be given.
Let $ np\_\_4 : {\iota}$ be given.
Assume the following.
\begin{equation}
{{k4\_glib\_000}={np\_\_4}}\label{hyp:egedpfhgmgjgcgpfadadad}
\end{equation}
Assume the following.
\begin{equation}
{{k3\_glib\_000}={np\_\_3}}\label{hyp:egddpfhgmgjgcgpfadadad}
\end{equation}
Assume the following.
\begin{equation}
{{k2\_glib\_000}={np\_\_2}}\label{hyp:egcdpfhgmgjgcgpfadadad}
\end{equation}
Assume the following.
\begin{equation}
{{k1\_glib\_000}={np\_\_1}}\label{hyp:egbdpfhgmgjgcgpfadadad}
\end{equation}
\begin{theorem}\label{thm:ehbdpfhgmgjgcgpfadadad}
$$\begin{array}{c}(k1\_glib\_000=np\_\_1){\unicdcdcdhd}((k2\_glib\_000=np\_\_2){\unicdcdcdhd}((k3\_glib\_000=\\
np\_\_3){\unicdcdcdhd}(k4\_glib\_000=np\_\_4)))\end{array}$$
\end{theorem}
\end{document}
