\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t1\_gr\_cy\_1 (TMcUALV16QoDmFch3BkYXJH2Cr9ZyowGwtV)}
\maketitle
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k4\_numbers : {\iota}$ be given.
Let $ k6\_numbers : {\iota}$ be given.
Let $ r3\_binop\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Let $ k44\_binop\_2 : {\iota}$ be given.
Let $ c3\_\_binop\_2 : {\iota}$ be given.
Assume the following.
\begin{equation}
{{{{r3\_binop\_1}~{k4\_numbers}}~{c3\_\_binop\_2}}~{k44\_binop\_2}}\label{hyp:mgddcdpfcgjgogpgahpfcd}
\end{equation}
Assume the following.
\begin{equation}
{{c3\_\_binop\_2}={k6\_numbers}}\label{hyp:egfgpfdgddpfpfcgjgogpgahpfcd}
\end{equation}
\begin{theorem}\label{thm:ehbdpfhgchpfdgjhpfbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k4\_numbers){\unicdbdjdcd}((X0=k6\_numbers){\unicdbdjdcd}(r3\_binop\_1~\\
k4\_numbers~X0~k44\_binop\_2))\end{array}$$
\end{theorem}
\end{document}
