\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t20\_topdim\_2 (TMFhN7ubYqJ4DJP2NEezyP8YhcFXgpxSNXA)}
\maketitle
Let $ v7\_ordinal1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ r1\_xxreal\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ k4\_topdim\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k15\_euclid : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k6\_numbers : {\iota}$ be given.
Let $ v3\_topdim\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v7\_ordinal1~X0){\unicdbdjdcd}(\preoh (r1\_xxreal\_0~X0~np\_\_1){\unicdcdcdhd}((X0{\unicdcdgdad}k6\_numbers){\unicdcdcdhd}\\
(X0{\unicdcdgdad}np\_\_1)))\end{array}
\label{hyp:ehcdfdpfogbgehpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}(v3\_topdim\_1~(k15\_euclid~np\_\_1)){\unicdcdcdhd}(k4\_topdim\_1~(k15\_euclid~np\_\_1)=\\
np\_\_1)\end{array}
\label{hyp:mgcdjdpfehpgahegjgngpfcd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}(v3\_topdim\_1~(k15\_euclid~k6\_numbers)){\unicdcdcdhd}(k4\_topdim\_1~(k15\_euclid~\\
k6\_numbers)=k6\_numbers)\end{array}
\label{hyp:mgcdidpfehpgahegjgngpfcd}
\end{equation}
\begin{theorem}\label{thm:ehcdadpfehpgahegjgngpfcd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (v7\_ordinal1~X0){\unicdbdjdcd}((r1\_xxreal\_0~X0~np\_\_1){\unicdbdjdcd}(k4\_topdim\_1~\\
(k15\_euclid~X0)=X0))\end{array}$$
\end{theorem}
\end{document}
