\documentclass{article}
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\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
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\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
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\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t21\_finseq\_3 (TMUUJbRwgqzt6ha26mYyyA2CY3tQfkarJty)}
\maketitle
Let $ v7\_ordinal1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k2\_finseq\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k2\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ k5\_card\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_tarski : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{({{v7\_ordinal1}~{X0}})}{\unicdbdjdcd}{({{{k5\_card\_1}~{({{k2\_finseq\_1}~{X0}})}}={X0}})}}}\label{hyp:ehfdhdpfggjgogdhfgbhpfbd}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{\unicdcdadad} X1 .  {{({{X0}{\unicdcdgdad}{X1}})}{\unicdbdjdcd}{({{{k5\_card\_1}~{({{{k2\_tarski}~{X0}}~{X1}})}}={np\_\_2}})}}}}\label{hyp:ehfdhdpfdgbgchegpfcd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}(k2\_finseq\_1~np\_\_1=k1\_tarski~np\_\_1){\unicdcdcdhd}(k2\_finseq\_1~np\_\_2=k2\_tarski~\\
np\_\_1~np\_\_2)\end{array}
\label{hyp:ehcdpfggjgogdhfgbhpfbd}
\end{equation}
\begin{theorem}\label{thm:ehcdbdpfggjgogdhfgbhpfdd}
$$\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  (v7\_ordinal1~X2){\unicdbdjdcd}((k2\_finseq\_1~\\
X2=k2\_tarski~X0~X1){\unicdbdjdcd}((X0=X1){\unicdcdcdid}((X2=np\_\_2){\unicdcdcdhd}(k2\_tarski~X0~X1=k2\_tarski~\\
np\_\_1~np\_\_2))))\end{array}$$
\end{theorem}
\end{document}
