\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
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\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t22\_polynom7 (TMUCZSbktmWCjp26kGtzh95VwJHEUn7nj4j)}
\maketitle
Let $ v2\_struct\_0 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ l2\_struct\_0 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ u1\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k2\_polynom1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}$ be given.
Let $ k15\_pre\_poly : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k4\_polynom7 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}$ be given.
Let $ k1\_xboole\_0 : {\iota}$ be given.
Let $ k6\_domain\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k16\_pre\_poly : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ v1\_funct\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v1\_funct\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Let $ v4\_polynom7 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Let $ k1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k2\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  ((\preoh v2\_struct\_0~X1){\unicdcdcdhd}(l2\_struct\_0~X1)){\unicdbdjdcd}\\
({\unicdcdadad} X2 .  ((v1\_funct\_1~X2){\unicdcdcdhd}((v1\_funct\_2~X2~(k15\_pre\_poly~X0)~\\
(u1\_struct\_0~X1)){\unicdcdcdhd}((v4\_polynom7~X2~X0~X1){\unicdcdcdhd}(m1\_subset\_1~X2~(k1\_zfmisc\_1~\\
(k2\_zfmisc\_1~(k15\_pre\_poly~X0)~(u1\_struct\_0~X1))))))){\unicdbdjdcd}((k2\_polynom1~\\
(k15\_pre\_poly~X0)~X1~X2=k1\_xboole\_0){\unicdcdcdid}(k2\_polynom1~(k15\_pre\_poly~\\
X0)~X1~X2=k6\_domain\_1~(k15\_pre\_poly~X0)~(k16\_pre\_poly~X0))))\end{array}
\label{hyp:ehbdfdpfahpgmgjhogpgnghd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  (((\preoh v2\_struct\_0~X1){\unicdcdcdhd}(l2\_struct\_0~\\
X1)){\unicdcdcdhd}(m1\_subset\_1~X2~(u1\_struct\_0~X1))){\unicdbdjdcd}((v1\_funct\_1~(k4\_polynom7~\\
X0~X1~X2)){\unicdcdcdhd}((v1\_funct\_2~(k4\_polynom7~X0~X1~X2)~(k15\_pre\_poly~X0)~\\
(u1\_struct\_0~X1)){\unicdcdcdhd}(v4\_polynom7~(k4\_polynom7~X0~X1~X2)~X0~X1)))\end{array}
\label{hyp:ggdgddpfahpgmgjhogpgnghd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  (((\preoh v2\_struct\_0~X1){\unicdcdcdhd}(l2\_struct\_0~\\
X1)){\unicdcdcdhd}(m1\_subset\_1~X2~(u1\_struct\_0~X1))){\unicdbdjdcd}((v1\_funct\_1~(k4\_polynom7~\\
X0~X1~X2)){\unicdcdcdhd}((v1\_funct\_2~(k4\_polynom7~X0~X1~X2)~(k15\_pre\_poly~X0)~\\
(u1\_struct\_0~X1)){\unicdcdcdhd}(m1\_subset\_1~(k4\_polynom7~X0~X1~X2)~(k1\_zfmisc\_1~\\
(k2\_zfmisc\_1~(k15\_pre\_poly~X0)~(u1\_struct\_0~X1))))))\end{array}
\label{hyp:egehpflgedpfahpgmgjhogpgnghd}
\end{equation}
\begin{theorem}\label{thm:ehcdcdpfahpgmgjhogpgnghd}
$$\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  ((\preoh v2\_struct\_0~X1){\unicdcdcdhd}(l2\_struct\_0~X1)){\unicdbdjdcd}\\
({\unicdcdadad} X2 .  (m1\_subset\_1~X2~(u1\_struct\_0~X1)){\unicdbdjdcd}((k2\_polynom1~\\
(k15\_pre\_poly~X0)~X1~(k4\_polynom7~X0~X1~X2)=k1\_xboole\_0){\unicdcdcdid}(k2\_polynom1~\\
(k15\_pre\_poly~X0)~X1~(k4\_polynom7~X0~X1~X2)=k6\_domain\_1~(k15\_pre\_poly~\\
X0)~(k16\_pre\_poly~X0))))\end{array}$$
\end{theorem}
\end{document}
