\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t23\_radix\_1 (TMVTJtJo7fquLZoav7Y8hQiop2VXfEK8JNQ)}
\maketitle
Let $ v7\_ordinal1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ r1\_radix\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ k11\_radix\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k2\_xcmplx\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k4\_radix\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}}$ be given.
Let $ k10\_radix\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v7\_ordinal1~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (v7\_ordinal1~X1){\unicdbdjdcd}((\\
r1\_radix\_1~np\_\_1~X0~X1){\unicdbdjdcd}(k4\_radix\_1~np\_\_1~X1~np\_\_1~(k10\_radix\_1~\\
X1~np\_\_1~X0)=X0)))\end{array}
\label{hyp:ehcdbdpfchbgegjgihpfbd}
\end{equation}
\begin{theorem}\label{thm:ehcdddpfchbgegjgihpfbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (v7\_ordinal1~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (v7\_ordinal1~X1){\unicdbdjdcd}({\unicdcdadad} X2 .  \\
(v7\_ordinal1~X2){\unicdbdjdcd}(((r1\_radix\_1~np\_\_1~X0~X1){\unicdcdcdhd}(r1\_radix\_1~np\_\_1~\\
X2~X1)){\unicdbdjdcd}(k11\_radix\_1~(k2\_xcmplx\_0~(k4\_radix\_1~np\_\_1~X1~np\_\_1~(\\
k10\_radix\_1~X1~np\_\_1~X0))~(k4\_radix\_1~np\_\_1~X1~np\_\_1~(k10\_radix\_1~\\
X1~np\_\_1~X2)))=k11\_radix\_1~(k2\_xcmplx\_0~X0~X2)))))\end{array}$$
\end{theorem}
\end{document}
