\documentclass{article}
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\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
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\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
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\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t23\_sysrel (TMPMC2dS7M5MTbxQYdnnrWFQg349A7e6U2S)}
\maketitle
Let $ v1\_relat\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ r1\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k3\_relat\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k6\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k4\_relat\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k10\_xtuple\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_xboole\_0 : {\iota}$ be given.
Let $ k3\_xboole\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k9\_xtuple\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{\unicdcdadad} X1 .  {{({{{r1\_tarski}~{X0}}~{X1}})}{\unicdbdjdcd}{({{{{k3\_xboole\_0}~{X0}}~{X1}}={X0}})}}}}\label{hyp:ehcdidpfihcgpgpgmgfgpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v1\_relat\_1~X0){\unicdbdjdcd}((((r1\_tarski~X0~(k3\_relat\_1~X0~X0)){\unicdcdcdhd}\\
(k3\_relat\_1~X0~(k6\_subset\_1~X0~(k4\_relat\_1~(k10\_xtuple\_0~X0)))=\\
k1\_xboole\_0)){\unicdbdjdcd}(r1\_tarski~(k4\_relat\_1~(k10\_xtuple\_0~X0))~X0)){\unicdcdcdhd}\\
(((r1\_tarski~X0~(k3\_relat\_1~X0~X0)){\unicdcdcdhd}(k3\_relat\_1~(k6\_subset\_1~\\
X0~(k4\_relat\_1~(k9\_xtuple\_0~X0)))~X0=k1\_xboole\_0)){\unicdbdjdcd}(r1\_tarski~\\
(k4\_relat\_1~(k9\_xtuple\_0~X0))~X0)))\end{array}
\label{hyp:ehcdcdpfdhjhdhchfgmg}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{\unicdcdadad} X1 .  {{{{k3\_xboole\_0}~{X0}}~{X1}}={{{k3\_xboole\_0}~{X1}}~{X0}}}}}\label{hyp:dgpgngngfhehbgehjgghjgehjhpflgddpfihcgpgpgmgfgpfad}
\end{equation}
\begin{theorem}\label{thm:ehcdddpfdhjhdhchfgmg}
$$\begin{array}{c}{\unicdcdadad} X0 .  (v1\_relat\_1~X0){\unicdbdjdcd}((((r1\_tarski~X0~(k3\_relat\_1~X0~X0)){\unicdcdcdhd}\\
(k3\_relat\_1~X0~(k6\_subset\_1~X0~(k4\_relat\_1~(k10\_xtuple\_0~X0)))=\\
k1\_xboole\_0)){\unicdbdjdcd}(k3\_xboole\_0~X0~(k4\_relat\_1~(k10\_xtuple\_0~X0))=\\
k4\_relat\_1~(k10\_xtuple\_0~X0))){\unicdcdcdhd}(((r1\_tarski~X0~(k3\_relat\_1~X0~\\
X0)){\unicdcdcdhd}(k3\_relat\_1~(k6\_subset\_1~X0~(k4\_relat\_1~(k9\_xtuple\_0~X0)))~\\
X0=k1\_xboole\_0)){\unicdbdjdcd}(k3\_xboole\_0~X0~(k4\_relat\_1~(k9\_xtuple\_0~X0))=\\
k4\_relat\_1~(k9\_xtuple\_0~X0))))\end{array}$$
\end{theorem}
\end{document}
