\documentclass{article}
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\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
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\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
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\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
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\begin{document}
\title{t26\_cqc\_the3 (TMQiEsc3muXFoMZmCKQMD1RiWtWLPxT8LZL)}
\maketitle
Let $ m1\_qc\_lang1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k3\_cqc\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ r4\_cqc\_the3 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Let $ r2\_cqc\_the3 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Let $ k4\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_qc\_lang1~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~X1~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}({\unicdcdadad} X2 .  (m1\_subset\_1~X2~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}({\unicdcdadad} X3 .  (m1\_subset\_1~X3~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}(((r2\_cqc\_the3~X0~X1~X2){\unicdcdcdhd}(r2\_cqc\_the3~X0~X2~\\
X3)){\unicdbdjdcd}(r2\_cqc\_the3~X0~X1~X3)))))\end{array}
\label{hyp:ehjdpfdgbhdgpfehigfgdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_qc\_lang1~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~X1~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}({\unicdcdadad} X2 .  (m1\_subset\_1~X2~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}({\unicdcdadad} X3 .  (m1\_subset\_1~X3~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}((r4\_cqc\_the3~X0~X1~X2){\unicdbdjdcd}(r4\_cqc\_the3~X0~(k4\_subset\_1~\\
(k3\_cqc\_lang~X0)~X1~X3)~(k4\_subset\_1~(k3\_cqc\_lang~X0)~X2~X3))))))\end{array}
\label{hyp:ehcdfdpfdgbhdgpfehigfgdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_qc\_lang1~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~X1~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}({\unicdcdadad} X2 .  (m1\_subset\_1~X2~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}((r4\_cqc\_the3~X0~X1~X2){\unicdbdjded}((r2\_cqc\_the3~X0~X1~\\
X2){\unicdcdcdhd}(r2\_cqc\_the3~X0~X2~X1)))))\end{array}
\label{hyp:ehbdidpfdgbhdgpfehigfgdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  ((m1\_subset\_1~X1~(k1\_zfmisc\_1~\\
X0)){\unicdcdcdhd}(m1\_subset\_1~X2~(k1\_zfmisc\_1~X0))){\unicdbdjdcd}(m1\_subset\_1~(k4\_subset\_1~\\
X0~X1~X2)~(k1\_zfmisc\_1~X0))\end{array}
\label{hyp:egehpflgedpfdhfhcgdhfgehpfbd}
\end{equation}
\begin{theorem}\label{thm:ehcdgdpfdgbhdgpfehigfgdd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (m1\_qc\_lang1~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~X1~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}({\unicdcdadad} X2 .  (m1\_subset\_1~X2~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}({\unicdcdadad} X3 .  (m1\_subset\_1~X3~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}({\unicdcdadad} X4 .  (m1\_subset\_1~X4~(k1\_zfmisc\_1~\\
(k3\_cqc\_lang~X0))){\unicdbdjdcd}(((r4\_cqc\_the3~X0~X1~X2){\unicdcdcdhd}(r2\_cqc\_the3~X0~(\\
k4\_subset\_1~(k3\_cqc\_lang~X0)~X1~X3)~X4)){\unicdbdjdcd}(r2\_cqc\_the3~X0~(k4\_subset\_1~\\
(k3\_cqc\_lang~X0)~X2~X3)~X4))))))\end{array}$$
\end{theorem}
\end{document}
