\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
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\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
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\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t26\_zf\_lang1 (TMcP66fXuE3844jj2rDQexd3QJnUXAoM4ws)}
\maketitle
Let $ v1\_zf\_lang : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ m2\_finseq\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k5\_numbers : {\iota}$ be given.
Let $ v9\_zf\_lang : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k26\_zf\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k20\_zf\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k22\_zf\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k21\_zf\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k7\_zf\_lang : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k11\_zf\_lang : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k25\_zf\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k6\_zf\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ m1\_finseq\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}({\unicdcdadad} X1 .  \\
((v1\_zf\_lang~X1){\unicdcdcdhd}(m2\_finseq\_1~X1~k5\_numbers)){\unicdbdjdcd}((k21\_zf\_lang~\\
(k7\_zf\_lang~X0~X1)=X0){\unicdcdcdhd}(k22\_zf\_lang~(k7\_zf\_lang~X0~X1)=X1)))\end{array}
\label{hyp:ehedpfkhggpfmgbgoghgbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}((\\
v9\_zf\_lang~X0){\unicdbdjdcd}(X0=k11\_zf\_lang~(k25\_zf\_lang~X0)~(k26\_zf\_lang~\\
X0)))\end{array}
\label{hyp:ehedhdpfkhggpfmgbgoghg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}(k20\_zf\_lang~\\
(k6\_zf\_lang~X0)=X0)\end{array}
\label{hyp:ehddpfkhggpfmgbgoghgbd}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{\unicdcdadad} X1 .  {{({{{m2\_finseq\_1}~{X1}}~{X0}})}{\unicdbdjded}{({{{m1\_finseq\_1}~{X1}}~{X0}})}}}}\label{hyp:chfgegfgggjgogjgehjgpgogpfngcdpfggjgogdhfgbhpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (((v1\_zf\_lang~X0){\unicdcdcdhd}(m1\_finseq\_1~X0~k5\_numbers)){\unicdcdcdhd}\\
((v1\_zf\_lang~X1){\unicdcdcdhd}(m1\_finseq\_1~X1~k5\_numbers))){\unicdbdjdcd}(v1\_zf\_lang~\\
(k7\_zf\_lang~X0~X1))\end{array}
\label{hyp:ggdgfdpfkhggpfmgbgoghg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m1\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}(v1\_zf\_lang~\\
(k6\_zf\_lang~X0))\end{array}
\label{hyp:ggdgedpfkhggpfmgbgoghg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  ((m1\_finseq\_1~X0~k5\_numbers){\unicdcdcdhd}(m1\_finseq\_1~\\
X1~k5\_numbers)){\unicdbdjdcd}(m2\_finseq\_1~(k7\_zf\_lang~X0~X1)~k5\_numbers)\end{array}
\label{hyp:egehpflghdpfkhggpfmgbgoghg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_finseq\_1~X0~k5\_numbers){\unicdbdjdcd}(m2\_finseq\_1~(k6\_zf\_lang~\\
X0)~k5\_numbers)\end{array}
\label{hyp:egehpflggdpfkhggpfmgbgoghg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m1\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}((\\
v1\_zf\_lang~(k26\_zf\_lang~X0)){\unicdcdcdhd}(m2\_finseq\_1~(k26\_zf\_lang~X0)~k5\_numbers))\end{array}
\label{hyp:egehpflgcdgdpfkhggpfmgbgoghg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m1\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}((\\
v1\_zf\_lang~(k25\_zf\_lang~X0)){\unicdcdcdhd}(m2\_finseq\_1~(k25\_zf\_lang~X0)~k5\_numbers))\end{array}
\label{hyp:egehpflgcdfdpfkhggpfmgbgoghg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}({\unicdcdadad} X1 .  \\
((v1\_zf\_lang~X1){\unicdcdcdhd}(m2\_finseq\_1~X1~k5\_numbers)){\unicdbdjdcd}(k11\_zf\_lang~\\
X0~X1=k6\_zf\_lang~(k7\_zf\_lang~X0~(k6\_zf\_lang~X1))))\end{array}
\label{hyp:egbdhdpfkhggpfmgbgoghg}
\end{equation}
\begin{theorem}\label{thm:ehcdgdpfkhggpfmgbgoghgbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}((\\
v9\_zf\_lang~X0){\unicdbdjdcd}(k26\_zf\_lang~X0=k20\_zf\_lang~(k22\_zf\_lang~(k20\_zf\_lang~\\
X0))))\end{array}$$
\end{theorem}
\end{document}
