\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t29\_nat\_2 (TMV9AmNNJMowuyT8PTpiZqTi2mN54xAmHRy)}
\maketitle
Let $ v1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v7\_ordinal1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ r1\_xxreal\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ k6\_numbers : {\iota}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v7\_ordinal1~X0){\unicdbdjdcd}(\preoh (\preoh r1\_xxreal\_0~np\_\_2~X0){\unicdcdcdhd}((X0{\unicdcdgdad}\\
k6\_numbers){\unicdcdcdhd}(X0{\unicdcdgdad}np\_\_1)))\end{array}
\label{hyp:ehcdddpfogbgehpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v7\_ordinal1~X0){\unicdbdjdcd}((v1\_zfmisc\_1~X0){\unicdbdjded}((X0=k6\_numbers){\unicdcdcdid}\\
(X0=np\_\_1)))\end{array}
\label{hyp:egbdpfogbgehpfcd}
\end{equation}
\begin{theorem}\label{thm:ehcdjdpfogbgehpfcd}
$$\begin{array}{c}{\unicdcdadad} X0 .  ((\preoh v1\_zfmisc\_1~X0){\unicdcdcdhd}(v7\_ordinal1~X0)){\unicdbdjdcd}(r1\_xxreal\_0~\\
np\_\_2~X0)\end{array}$$
\end{theorem}
\end{document}
