\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t2\_altcat\_1 (TMYfECreTW6WUbdygk1sL9xf5zkLP2x54xb)}
\maketitle
Let $ k1\_funct\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_xboole\_0 : {\iota}$ be given.
Let $ k1\_tarski : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k4\_relat\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{{{k1\_funct\_2}~{k1\_xboole\_0}}~{X0}}={{k1\_tarski}~{k1\_xboole\_0}}}}\label{hyp:ehfdhdpfggfhogdgehpffd}
\end{equation}
Assume the following.
\begin{equation}
{{{k4\_relat\_1}~{k1\_xboole\_0}}={k1\_xboole\_0}}\label{hyp:ehfdfdpfchfgmgbgehpfbd}
\end{equation}
\begin{theorem}\label{thm:ehcdpfbgmgehdgbgehpfbd}
${{{{k1\_funct\_2}~{k1\_xboole\_0}}~{k1\_xboole\_0}}={{k1\_tarski}~{({{k4\_relat\_1}~{k1\_xboole\_0}})}}}$.
\end{theorem}
\end{document}
