\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t2\_ami\_5 (TMRXc2hTDNd5qKAs7S6zCd7ffdBqktCPCLq)}
\maketitle
Let $ v1\_ami\_2 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ u1\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_ami\_3 : {\iota}$ be given.
Let $ k4\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k5\_numbers : {\iota}$ be given.
Let $ k2\_ami\_2 : {\iota}$ be given.
Assume the following.
\begin{equation}
{\preoh{{{k5\_numbers} \in {k2\_ami\_2}}}}\label{hyp:ehcdadpfbgngjgpfcd}
\end{equation}
Assume the following.
\begin{equation}
{{{k4\_struct\_0}~{k1\_ami\_3}}={k5\_numbers}}\label{hyp:ehbdpfbgngjgpfdd}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{({{v1\_ami\_2}~{X0}})}{\unicdbdjded}{({{X0} \in {k2\_ami\_2}})}}}\label{hyp:egbdgdpfbgngjgpfcd}
\end{equation}
\begin{theorem}\label{thm:ehcdpfbgngjgpffd}
$$\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_ami\_2~X0){\unicdcdcdhd}(m1\_subset\_1~X0~(u1\_struct\_0~k1\_ami\_3))){\unicdbdjdcd}\\
(X0{\unicdcdgdad}k4\_struct\_0~k1\_ami\_3)\end{array}$$
\end{theorem}
\end{document}
