\documentclass{article}
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\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
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\begin{document}
\title{t30\_topgen\_3 (TMHn3xLtEXVvKkYBQFQRrN1D3SQ5kVZjwLB)}
\maketitle
Let $ k4\_ordinal1 : {\iota}$ be given.
Let $ k3\_topgen\_3 : {\iota}$ be given.
Let $ k1\_card\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k3\_card\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ k1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k5\_numbers : {\iota}$ be given.
Assume the following.
\begin{equation}
{{{k1\_card\_1}~{k4\_ordinal1}}={k4\_ordinal1}}\label{hyp:ehedhdpfdgbgchegpfbd}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{{{k3\_card\_2}~{np\_\_2}}~{({{k1\_card\_1}~{X0}})}}={{k1\_card\_1}~{({{k1\_zfmisc\_1}~{X0}})}}}}\label{hyp:ehddbdpfdgbgchegpfcd}
\end{equation}
Assume the following.
\begin{equation}
{{k3\_topgen\_3}={{{k3\_card\_2}~{np\_\_2}}~{k4\_ordinal1}}}\label{hyp:ehcdjdpfehpgahhgfgogpfdd}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{{k1\_card\_1}~{X0}} \in {{k1\_card\_1}~{({{k1\_zfmisc\_1}~{X0}})}}}}\label{hyp:ehbdedpfdgbgchegpfbd}
\end{equation}
Assume the following.
\begin{equation}
{{k5\_numbers}={k4\_ordinal1}}\label{hyp:chfgegfgggjgogjgehjgpgogpflgfdpfogfhngcgfgchdh}
\end{equation}
\begin{theorem}\label{thm:ehddadpfehpgahhgfgogpfdd}
${{k4\_ordinal1} \in {k3\_topgen\_3}}$.
\end{theorem}
\end{document}
