\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t35\_relset\_2 (TMa8dhrJfyM9NFLjXNNJ9cgnG8tMrH9rGVg)}
\maketitle
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k2\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k6\_relset\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 : \iota{\unicdbdjdcd}o .  {\unicdcdadad} X2 : \iota{\unicdbdjdcd}\iota .  {\unicdcdadad} X3 .  \\
m1\_subset\_1~(ReplSep~(toset~({\uniddcgcg} X4 : \iota .  m1\_subset\_1~X4~X3))~(\\
{\uniddcgcg} X4 : \iota .  X1~X4)~({\uniddcgcg} X4 : \iota .  X2~X4))~(k1\_zfmisc\_1~X0)\end{array}
\label{hyp:dhidpfegpgngbgjgogpfbd}
\end{equation}
\begin{theorem}\label{thm:ehddfdpfchfgmgdhfgehpfcd}
$$\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  (m1\_subset\_1~X2~(k1\_zfmisc\_1~\\
(k1\_zfmisc\_1~(k2\_zfmisc\_1~X0~X1)))){\unicdbdjdcd}({\unicdcdadad} X3 .  {\unicdcdadad} X4 .  {\unicdcdadad} X5 .  \\
(m1\_subset\_1~X5~(k1\_zfmisc\_1~X3)){\unicdbdjdcd}(m1\_subset\_1~(ReplSep~(toset~\\
({\uniddcgcg} X6 : \iota .  m1\_subset\_1~X6~(k1\_zfmisc\_1~(k2\_zfmisc\_1~X3~X4))))~\\
({\uniddcgcg} X6 : \iota .  X6 \in X2)~({\uniddcgcg} X6 : \iota .  k6\_relset\_2~X3~X4~X5~X6))~(k1\_zfmisc\_1~\\
(k1\_zfmisc\_1~X4))))\end{array}$$
\end{theorem}
\end{document}
