\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t36\_kurato\_1 (TMV4T3AaPuQqego2u9oLnFZp6MSNiXf78vk)}
\maketitle
Let $ k1\_tops\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k3\_topmetr : {\iota}$ be given.
Let $ k2\_pre\_topc : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k6\_kurato\_1 : {\iota}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}k2\_pre\_topc~k3\_topmetr~(k1\_tops\_1~k3\_topmetr~(k2\_pre\_topc~k3\_topmetr~\\
k6\_kurato\_1)){\unicdcdgdad}k2\_pre\_topc~k3\_topmetr~(k1\_tops\_1~k3\_topmetr~\\
k6\_kurato\_1)\end{array}
\label{hyp:ehddbdpflgfhchbgehpgpfbd}
\end{equation}
\begin{theorem}\label{thm:ehddgdpflgfhchbgehpgpfbd}
$$\begin{array}{c}k1\_tops\_1~k3\_topmetr~(k2\_pre\_topc~k3\_topmetr~k6\_kurato\_1){\unicdcdgdad}k1\_tops\_1~\\
k3\_topmetr~k6\_kurato\_1\end{array}$$
\end{theorem}
\end{document}
