\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t3\_glib\_003 (TMVXbNoZ8mRBA7hHEFm1vvwWnFXmi4fqWBU)}
\maketitle
Let $ k2\_glib\_003 : {\iota}$ be given.
Let $ np\_\_5 : {\iota}$ be given.
Let $ k3\_glib\_003 : {\iota}$ be given.
Let $ np\_\_6 : {\iota}$ be given.
Let $ k4\_glib\_003 : {\iota}$ be given.
Let $ np\_\_7 : {\iota}$ be given.
Assume the following.
\begin{equation}
{{k4\_glib\_003}={np\_\_7}}\label{hyp:egddpfhgmgjgcgpfadaddd}
\end{equation}
Assume the following.
\begin{equation}
{{k3\_glib\_003}={np\_\_6}}\label{hyp:egcdpfhgmgjgcgpfadaddd}
\end{equation}
Assume the following.
\begin{equation}
{{k2\_glib\_003}={np\_\_5}}\label{hyp:egbdpfhgmgjgcgpfadaddd}
\end{equation}
\begin{theorem}\label{thm:ehddpfhgmgjgcgpfadaddd}
${{({{k2\_glib\_003}={np\_\_5}})}{\unicdcdcdhd}{({{({{k3\_glib\_003}={np\_\_6}})}{\unicdcdcdhd}{({{k4\_glib\_003}={np\_\_7}})}})}}$.
\end{theorem}
\end{document}
