\documentclass{article}
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\newtheorem{conjecture}{Conjecture}
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\begin{document}
\title{t3\_sin\_cos9 (TMHTeGe7xRqKLbe4Zg8dRPtLzH3DhRxUUfN)}
\maketitle
Let $ r2\_fdiff\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k29\_sin\_cos : {\iota}$ be given.
Let $ k2\_rcomp\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_real\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k10\_real\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k32\_sin\_cos : {\iota}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k1\_numbers : {\iota}$ be given.
Let $ k1\_fdiff\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ k5\_square\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_seq\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k19\_sin\_cos : {\iota}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k1\_numbers){\unicdbdjdcd}((X0 \in k2\_rcomp\_1~(k1\_real\_1~\\
(k10\_real\_1~k32\_sin\_cos~np\_\_2))~(k10\_real\_1~k32\_sin\_cos~np\_\_2)){\unicdbdjdcd}\\
(k1\_fdiff\_1~k29\_sin\_cos~X0=k10\_real\_1~np\_\_1~(k5\_square\_1~(k1\_seq\_1~\\
k19\_sin\_cos~X0))))\end{array}
\label{hyp:mgfdpfdhjgogpfdgpgdhjd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}r2\_fdiff\_1~k29\_sin\_cos~(k2\_rcomp\_1~(k1\_real\_1~(k10\_real\_1~k32\_sin\_cos~\\
np\_\_2))~(k10\_real\_1~k32\_sin\_cos~np\_\_2))\end{array}
\label{hyp:mgddpfdhjgogpfdgpgdhjd}
\end{equation}
\begin{theorem}\label{thm:ehddpfdhjgogpfdgpgdhjd}
$$\begin{array}{c}(r2\_fdiff\_1~k29\_sin\_cos~(k2\_rcomp\_1~(k1\_real\_1~(k10\_real\_1~k32\_sin\_cos~\\
np\_\_2))~(k10\_real\_1~k32\_sin\_cos~np\_\_2))){\unicdcdcdhd}({\unicdcdadad} X0 .  (m1\_subset\_1~\\
X0~k1\_numbers){\unicdbdjdcd}((X0 \in k2\_rcomp\_1~(k1\_real\_1~(k10\_real\_1~k32\_sin\_cos~\\
np\_\_2))~(k10\_real\_1~k32\_sin\_cos~np\_\_2)){\unicdbdjdcd}(k1\_fdiff\_1~k29\_sin\_cos~\\
X0=k10\_real\_1~np\_\_1~(k5\_square\_1~(k1\_seq\_1~k19\_sin\_cos~X0)))))\end{array}$$
\end{theorem}
\end{document}
