\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t41\_tdlat\_3 (TMSYEwQmTBDzZVQzG97qr2zGMShfGp7QQ3J)}
\maketitle
Let $ v2\_struct\_0 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v2\_pre\_topc : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v4\_tdlat\_3 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ l1\_pre\_topc : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k4\_tdlat\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k8\_tdlat\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k2\_tdlat\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k6\_tdlat\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k3\_tdlat\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k7\_tdlat\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_tdlat\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k5\_tdlat\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ g3\_lattices : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((\preoh v2\_struct\_0~X0){\unicdcdcdhd}((v2\_pre\_topc~X0){\unicdcdcdhd}((v4\_tdlat\_3~\\
X0){\unicdcdcdhd}(l1\_pre\_topc~X0)))){\unicdbdjdcd}((k2\_tdlat\_1~X0=k6\_tdlat\_1~X0){\unicdcdcdhd}(k3\_tdlat\_1~\\
X0=k7\_tdlat\_1~X0))\end{array}
\label{hyp:ehedadpfehegmgbgehpfdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((\preoh v2\_struct\_0~X0){\unicdcdcdhd}((v2\_pre\_topc~X0){\unicdcdcdhd}((v4\_tdlat\_3~\\
X0){\unicdcdcdhd}(l1\_pre\_topc~X0)))){\unicdbdjdcd}(k1\_tdlat\_1~X0=k5\_tdlat\_1~X0)\end{array}
\label{hyp:ehddjdpfehegmgbgehpfdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v2\_pre\_topc~X0){\unicdcdcdhd}(l1\_pre\_topc~X0)){\unicdbdjdcd}(k8\_tdlat\_1~\\
X0=g3\_lattices~(k5\_tdlat\_1~X0)~(k6\_tdlat\_1~X0)~(k7\_tdlat\_1~X0))\end{array}
\label{hyp:egidpfehegmgbgehpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v2\_pre\_topc~X0){\unicdcdcdhd}(l1\_pre\_topc~X0)){\unicdbdjdcd}(k4\_tdlat\_1~\\
X0=g3\_lattices~(k1\_tdlat\_1~X0)~(k2\_tdlat\_1~X0)~(k3\_tdlat\_1~X0))\end{array}
\label{hyp:egedpfehegmgbgehpfbd}
\end{equation}
\begin{theorem}\label{thm:ehedbdpfehegmgbgehpfdd}
$$\begin{array}{c}{\unicdcdadad} X0 .  ((\preoh v2\_struct\_0~X0){\unicdcdcdhd}((v2\_pre\_topc~X0){\unicdcdcdhd}((v4\_tdlat\_3~\\
X0){\unicdcdcdhd}(l1\_pre\_topc~X0)))){\unicdbdjdcd}(k4\_tdlat\_1~X0=k8\_tdlat\_1~X0)\end{array}$$
\end{theorem}
\end{document}
