\documentclass{article}
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\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
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\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
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\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t43\_orders\_2 (TMMbao7mTQjiZDvhbnVn8PPtyEXp8XbBGXd)}
\maketitle
Let $ v2\_struct\_0 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v3\_orders\_2 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v4\_orders\_2 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v5\_orders\_2 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ l1\_orders\_2 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ m1\_orders\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k1\_orders\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ u1\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k3\_tarski : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k4\_orders\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_xboole\_0 : {\iota}$ be given.
Let $ r1\_xboole\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ m2\_orders\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (\preoh ({\unicdcdaddd} X1 .  (X1{\unicdcdgdad}k1\_xboole\_0){\unicdcdcdhd}(X1 \in X0)){\unicdcdcdhd}(k3\_tarski~\\
X0=k1\_xboole\_0)){\unicdcdcdhd}(\preoh (k3\_tarski~X0{\unicdcdgdad}k1\_xboole\_0){\unicdcdcdhd}({\unicdcdadad} X1 .  \\
\preoh (X1{\unicdcdgdad}k1\_xboole\_0){\unicdcdcdhd}(X1 \in X0)))\end{array}
\label{hyp:ehgdpfpgchegfgchdhpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (\preoh (\preoh r1\_xboole\_0~X0~X0){\unicdcdcdhd}(X0=k1\_xboole\_0)){\unicdcdcdhd}(\preoh (X0{\unicdcdgdad}\\
k1\_xboole\_0){\unicdcdcdhd}(r1\_xboole\_0~X0~X0))\end{array}
\label{hyp:ehgdgdpfihcgpgpgmgfgpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((\preoh v2\_struct\_0~X0){\unicdcdcdhd}((v3\_orders\_2~X0){\unicdcdcdhd}((v4\_orders\_2~\\
X0){\unicdcdcdhd}((v5\_orders\_2~X0){\unicdcdcdhd}(l1\_orders\_2~X0))))){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_orders\_1~\\
X1~(k1\_orders\_1~(u1\_struct\_0~X0))){\unicdbdjdcd}({\unicdcdadad} X2 .  (m2\_orders\_2~\\
X2~X0~X1){\unicdbdjdcd}({\unicdcdadad} X3 .  (m2\_orders\_2~X3~X0~X1){\unicdbdjdcd}(\preoh r1\_xboole\_0~X2~X3))))\end{array}
\label{hyp:ehedadpfpgchegfgchdhpfcd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (((\preoh v2\_struct\_0~X0){\unicdcdcdhd}((v3\_orders\_2~X0){\unicdcdcdhd}\\
((v4\_orders\_2~X0){\unicdcdcdhd}((v5\_orders\_2~X0){\unicdcdcdhd}(l1\_orders\_2~X0))))){\unicdcdcdhd}(\\
m1\_orders\_1~X1~(k1\_orders\_1~(u1\_struct\_0~X0)))){\unicdbdjdcd}({\unicdcdaddd} X2 .  \\
m2\_orders\_2~X2~X0~X1)\end{array}
\label{hyp:fgihjgdhehfgogdgfgpfngcdpfpgchegfgchdhpfcd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((\preoh v2\_struct\_0~X0){\unicdcdcdhd}((v3\_orders\_2~X0){\unicdcdcdhd}((v4\_orders\_2~\\
X0){\unicdcdcdhd}((v5\_orders\_2~X0){\unicdcdcdhd}(l1\_orders\_2~X0))))){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_orders\_1~\\
X1~(k1\_orders\_1~(u1\_struct\_0~X0))){\unicdbdjdcd}({\unicdcdadad} X2 .  (X2=k4\_orders\_2~\\
X0~X1){\unicdbdjded}({\unicdcdadad} X3 .  (X3 \in X2){\unicdbdjded}(m2\_orders\_2~X3~X0~X1))))\end{array}
\label{hyp:egbdddpfpgchegfgchdhpfcd}
\end{equation}
\begin{theorem}\label{thm:ehedddpfpgchegfgchdhpfcd}
$$\begin{array}{c}{\unicdcdadad} X0 .  ((\preoh v2\_struct\_0~X0){\unicdcdcdhd}((v3\_orders\_2~X0){\unicdcdcdhd}((v4\_orders\_2~\\
X0){\unicdcdcdhd}((v5\_orders\_2~X0){\unicdcdcdhd}(l1\_orders\_2~X0))))){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_orders\_1~\\
X1~(k1\_orders\_1~(u1\_struct\_0~X0))){\unicdbdjdcd}(k3\_tarski~(k4\_orders\_2~X0~\\
X1){\unicdcdgdad}k1\_xboole\_0))\end{array}$$
\end{theorem}
\end{document}
