\documentclass{article}
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\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
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\newcommand\unicdbdjded{\Leftrightarrow}
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\newcommand\preoh[1]{\lnot #1}
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\begin{document}
\title{t4\_arytm\_0 (TMSLP8RzLXuSLuQfXCTcJrYXDXqGFi3fBsZ)}
\maketitle
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k2\_arytm\_2 : {\iota}$ be given.
Let $ k2\_arytm\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_numbers : {\iota}$ be given.
Let $ r1\_arytm\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k1\_arytm\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k11\_arytm\_3 : {\iota}$ be given.
Let $ v1\_xboole\_0 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k4\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ r1\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k2\_arytm\_2){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~k2\_arytm\_2){\unicdbdjdcd}(\preoh (\preoh r1\_arytm\_2~X0~X1){\unicdcdcdhd}(k1\_arytm\_1~X0~X1=k11\_arytm\_3)))\end{array}
\label{hyp:ehjdpfbgchjhehngpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (m1\_subset\_1~X0~X1){\unicdbdjdcd}((v1\_xboole\_0~X1){\unicdcdcdid}\\
(X0 \in X1))\end{array}
\label{hyp:ehcdpfdhfhcgdhfgeh}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k2\_arytm\_2){\unicdbdjdcd}((X0{\unicdcdgdad}k11\_arytm\_3){\unicdbdjdcd}(\\
k4\_tarski~k11\_arytm\_3~X0 \in k1\_numbers))\end{array}
\label{hyp:ehcdpfbgchjhehngpfad}
\end{equation}
Assume the following.
\begin{equation}
{{{r1\_tarski}~{k2\_arytm\_2}}~{k1\_numbers}}\label{hyp:mgedpfogfhngcgfgchdh}
\end{equation}
Assume the following.
\begin{equation}
{\preoh{{{v1\_xboole\_0}~{k2\_arytm\_2}}}}\label{hyp:ggdgcdpfbgchjhehngpfcd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  ((m1\_subset\_1~X0~k2\_arytm\_2){\unicdcdcdhd}(m1\_subset\_1~\\
X1~k2\_arytm\_2)){\unicdbdjdcd}(m1\_subset\_1~(k1\_arytm\_1~X0~X1)~k2\_arytm\_2)\end{array}
\label{hyp:egehpflgbdpfbgchjhehngpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (r1\_tarski~X0~X1){\unicdbdjded}({\unicdcdadad} X2 .  (X2 \in X0){\unicdbdjdcd}\\
(X2 \in X1))\end{array}
\label{hyp:egddpfehbgchdhlgjg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k2\_arytm\_2){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~k2\_arytm\_2){\unicdbdjdcd}(((r1\_arytm\_2~X1~X0){\unicdbdjdcd}(k2\_arytm\_1~X0~X1=k1\_arytm\_1~\\
X0~X1)){\unicdcdcdhd}((\preoh r1\_arytm\_2~X1~X0){\unicdbdjdcd}(k2\_arytm\_1~X0~X1=k4\_tarski~k11\_arytm\_3~\\
(k1\_arytm\_1~X1~X0)))))\end{array}
\label{hyp:egcdpfbgchjhehngpfbd}
\end{equation}
\begin{theorem}\label{thm:ehedpfbgchjhehngpfad}
$$\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k2\_arytm\_2){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~k2\_arytm\_2){\unicdbdjdcd}(k2\_arytm\_1~X0~X1 \in k1\_numbers))\end{array}$$
\end{theorem}
\end{document}
