\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t4\_e\_siec (TMYwykaFETRHjgx3LR7x7XDrkTS8kRChkm5)}
\maketitle
Let $ v2\_e\_siec : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ g1\_e\_siec : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}$ be given.
Let $ k1\_xboole\_0 : {\iota}$ be given.
Let $ v3\_e\_siec : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ l1\_e\_siec : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v2\_e\_siec~(g1\_e\_siec~X0~k1\_xboole\_0~k1\_xboole\_0)){\unicdcdcdhd}\\
((v3\_e\_siec~(g1\_e\_siec~X0~k1\_xboole\_0~k1\_xboole\_0)){\unicdcdcdhd}(l1\_e\_siec~\\
(g1\_e\_siec~X0~k1\_xboole\_0~k1\_xboole\_0)))\end{array}
\label{hyp:ehcdpffgpfdhjgfgdg}
\end{equation}
\begin{theorem}\label{thm:ehedpffgpfdhjgfgdg}
$$\begin{array}{c}(v2\_e\_siec~(g1\_e\_siec~k1\_xboole\_0~k1\_xboole\_0~k1\_xboole\_0)){\unicdcdcdhd}\\
((v3\_e\_siec~(g1\_e\_siec~k1\_xboole\_0~k1\_xboole\_0~k1\_xboole\_0)){\unicdcdcdhd}\\
(l1\_e\_siec~(g1\_e\_siec~k1\_xboole\_0~k1\_xboole\_0~k1\_xboole\_0)))\end{array}$$
\end{theorem}
\end{document}
