\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
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\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t50\_abcmiz\_1 (TMJzKnd6sJtdAFPw2yMwTCYcaiXM8kcxfKC)}
\maketitle
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k2\_abcmiz\_1 : {\iota}$ be given.
Let $ v1\_instalg1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v1\_abcmiz\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v3\_abcmiz\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ l1\_msualg\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k35\_abcmiz\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_trees\_4 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k4\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k8\_abcmiz\_1 : {\iota}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ k2\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_tarski : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{\unicdcdadad} X1 .  {{({{{k1\_trees\_4}~{X0}}={{k1\_trees\_4}~{X1}}})}{\unicdbdjdcd}{({{X0}={X1}})}}}}\label{hyp:ehedpfehchfgfgdhpfed}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  {\unicdcdadad} X3 .  (k4\_tarski~X0~X1=\\
k4\_tarski~X2~X3){\unicdbdjdcd}((X0=X2){\unicdcdcdhd}(X1=X3))\end{array}
\label{hyp:ehbdpfihehfhahmgfgpfad}
\end{equation}
Assume the following.
\begin{equation}
{{k8\_abcmiz\_1}={np\_\_2}}\label{hyp:eggdpfbgcgdgngjgkhpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  k4\_tarski~X0~X1=k2\_tarski~(k2\_tarski~X0~\\
X1)~(k1\_tarski~X0)\end{array}
\label{hyp:egfdpfehbgchdhlgjg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k2\_abcmiz\_1){\unicdbdjdcd}({\unicdcdadad} X1 .  ((v1\_instalg1~\\
X1){\unicdcdcdhd}((v1\_abcmiz\_1~X1){\unicdcdcdhd}((v3\_abcmiz\_1~X1){\unicdcdcdhd}(l1\_msualg\_1~X1)))){\unicdbdjdcd}\\
(k35\_abcmiz\_1~X0~X1=k1\_trees\_4~(k4\_tarski~X0~k8\_abcmiz\_1)))\end{array}
\label{hyp:egddedpfbgcgdgngjgkhpfbd}
\end{equation}
\begin{theorem}\label{thm:ehfdadpfbgcgdgngjgkhpfbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k2\_abcmiz\_1){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~k2\_abcmiz\_1){\unicdbdjdcd}({\unicdcdadad} X2 .  ((v1\_instalg1~X2){\unicdcdcdhd}((v1\_abcmiz\_1~\\
X2){\unicdcdcdhd}((v3\_abcmiz\_1~X2){\unicdcdcdhd}(l1\_msualg\_1~X2)))){\unicdbdjdcd}({\unicdcdadad} X3 .  ((v1\_instalg1~\\
X3){\unicdcdcdhd}((v1\_abcmiz\_1~X3){\unicdcdcdhd}((v3\_abcmiz\_1~X3){\unicdcdcdhd}(l1\_msualg\_1~X3)))){\unicdbdjdcd}\\
((k35\_abcmiz\_1~X0~X2=k35\_abcmiz\_1~X1~X3){\unicdbdjdcd}(X0=X1)))))\end{array}$$
\end{theorem}
\end{document}
