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\begin{document}
\title{t52\_sin\_cos3 (TMQCuBq5SXjzMe8XczqFcbUQBaBbXoFvmC9)}
\maketitle
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k5\_numbers : {\iota}$ be given.
Let $ k2\_numbers : {\iota}$ be given.
Let $ k15\_sin\_cos : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k5\_binop\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k7\_complex1 : {\iota}$ be given.
Let $ k2\_comseq\_3 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k3\_binop\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k10\_funct\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}}$ be given.
Let $ k2\_sin\_cos3 : {\iota}$ be given.
Let $ k1\_sin\_cos3 : {\iota}$ be given.
Let $ v1\_xcmplx\_0 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k3\_xcmplx\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_xcmplx\_0 : {\iota}$ be given.
Let $ k4\_ordinal1 : {\iota}$ be given.
Let $ v6\_membered : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v1\_membered : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v7\_ordinal1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k5\_numbers){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~k2\_numbers){\unicdbdjdcd}(k2\_comseq\_3~(k3\_binop\_2~(k10\_funct\_2~k2\_numbers~\\
k2\_numbers~k2\_sin\_cos3~X1)~(k5\_binop\_2~k7\_complex1~(k10\_funct\_2~\\
k2\_numbers~k2\_numbers~k1\_sin\_cos3~X1)))~X0=k3\_binop\_2~(k10\_funct\_2~\\
k2\_numbers~k2\_numbers~k2\_sin\_cos3~(k5\_binop\_2~X0~X1))~(k5\_binop\_2~\\
k7\_complex1~(k10\_funct\_2~k2\_numbers~k2\_numbers~k1\_sin\_cos3~(\\
k5\_binop\_2~X0~X1)))))\end{array}
\label{hyp:ehfdadpfdhjgogpfdgpgdhdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v1\_xcmplx\_0~X0){\unicdbdjdcd}(k15\_sin\_cos~(k5\_binop\_2~k7\_complex1~\\
X0)=k3\_binop\_2~(k10\_funct\_2~k2\_numbers~k2\_numbers~k2\_sin\_cos3~\\
X0)~(k5\_binop\_2~k7\_complex1~(k10\_funct\_2~k2\_numbers~k2\_numbers~\\
k1\_sin\_cos3~X0)))\end{array}
\label{hyp:ehddgdpfdhjgogpfdgpgdhdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  ((v1\_xcmplx\_0~X0){\unicdcdcdhd}((v1\_xcmplx\_0~\\
X1){\unicdcdcdhd}(v1\_xcmplx\_0~X2))){\unicdbdjdcd}(k3\_xcmplx\_0~(k3\_xcmplx\_0~X0~X1)~X2=k3\_xcmplx\_0~\\
X0~(k3\_xcmplx\_0~X1~X2))\end{array}
\label{hyp:dhahdghdpfbgchjgehigng}
\end{equation}
Assume the following.
\begin{equation}
{{k7\_complex1}={k1\_xcmplx\_0}}\label{hyp:chfgegfgggjgogjgehjgpgogpflghdpfdgpgngahmgfgihbd}
\end{equation}
Assume the following.
\begin{equation}
{{k5\_numbers}={k4\_ordinal1}}\label{hyp:chfgegfgggjgogjgehjgpgogpflgfdpfogfhngcgfgchdh}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  ((v1\_xcmplx\_0~X0){\unicdcdcdhd}(v1\_xcmplx\_0~X1)){\unicdbdjdcd}(\\
k5\_binop\_2~X0~X1=k3\_xcmplx\_0~X0~X1)\end{array}
\label{hyp:chfgegfgggjgogjgehjgpgogpflgfdpfcgjgogpgahpfcd}
\end{equation}
Assume the following.
\begin{equation}
{{v6\_membered}~{k4\_ordinal1}}\label{hyp:ggdggdpfngfgngcgfgchfgeg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  ((v1\_xcmplx\_0~X0){\unicdcdcdhd}(v1\_xcmplx\_0~X1)){\unicdbdjdcd}(\\
v1\_xcmplx\_0~(k3\_xcmplx\_0~X0~X1))\end{array}
\label{hyp:ggdgddpfihdgngahmgihpfad}
\end{equation}
Assume the following.
\begin{equation}
{{v1\_xcmplx\_0}~{k1\_xcmplx\_0}}\label{hyp:ggdgbdpfihdgngahmgihpfad}
\end{equation}
Assume the following.
\begin{equation}
{{v1\_membered}~{k2\_numbers}}\label{hyp:ggdgbdpfngfgngcgfgchfgeg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  ((v1\_xcmplx\_0~X0){\unicdcdcdhd}(v1\_xcmplx\_0~X1)){\unicdbdjdcd}(\\
k3\_xcmplx\_0~X0~X1=k3\_xcmplx\_0~X1~X0)\end{array}
\label{hyp:dgpgngngfhehbgehjgghjgehjhpflgddpfihdgngahmgihpfad}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{({{v7\_ordinal1}~{X0}})}{\unicdbdjdcd}{({{v1\_xcmplx\_0}~{X0}})}}}\label{hyp:dgdgcdpfihdgngahmgihpfad}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v6\_membered~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~X1~X0){\unicdbdjdcd}\\
(v7\_ordinal1~X1))\end{array}
\label{hyp:dgdgbdhdpfngfgngcgfgchfgeg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v1\_membered~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~X1~X0){\unicdbdjdcd}\\
(v1\_xcmplx\_0~X1))\end{array}
\label{hyp:dgdgbdcdpfngfgngcgfgchfgeg}
\end{equation}
\begin{theorem}\label{thm:ehfdcdpfdhjgogpfdgpgdhdd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k5\_numbers){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~k2\_numbers){\unicdbdjdcd}(k15\_sin\_cos~(k5\_binop\_2~(k5\_binop\_2~k7\_complex1~\\
X0)~X1)=k2\_comseq\_3~(k3\_binop\_2~(k10\_funct\_2~k2\_numbers~k2\_numbers~\\
k2\_sin\_cos3~X1)~(k5\_binop\_2~k7\_complex1~(k10\_funct\_2~k2\_numbers~\\
k2\_numbers~k1\_sin\_cos3~X1)))~X0))\end{array}$$
\end{theorem}
\end{document}
