\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t5\_scmyciel (TMFdHVaAHCQp8DAAYhLN7v2c8oy6eGFqguP)}
\maketitle
Let $ r1\_ordinal1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ np\_\_3 : {\iota}$ be given.
Let $ k1\_card\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (r1\_ordinal1~np\_\_3~(k1\_card\_1~X0)){\unicdbdjded}({\unicdcdaddd} X1 .  {\unicdcdaddd} X2 .  \\
{\unicdcdaddd} X3 .  (X1 \in X0){\unicdcdcdhd}((X2 \in X0){\unicdcdcdhd}((X3 \in X0){\unicdcdcdhd}((X1{\unicdcdgdad}X2){\unicdcdcdhd}((X1{\unicdcdgdad}X3){\unicdcdcdhd}(\\
X2{\unicdcdgdad}X3))))))\end{array}
\label{hyp:ehfdpfahfgogdgjgmgpfbd}
\end{equation}
\begin{theorem}\label{thm:ehfdpfdhdgngjhdgjgfgmg}
$$\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  \preoh (r1\_ordinal1~np\_\_3~(k1\_card\_1~X0)){\unicdcdcdhd}({\unicdcdadad} X2 .  \\
{\unicdcdadad} X3 .  \preoh (X2 \in X0){\unicdcdcdhd}((X3 \in X0){\unicdcdcdhd}((X2{\unicdcdgdad}X1){\unicdcdcdhd}((X3{\unicdcdgdad}X1){\unicdcdcdhd}(X2{\unicdcdgdad}X3)))))\end{array}$$
\end{theorem}
\end{document}
