\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t6\_ff\_siec (TMWzLuAzBZ43YSSKP2kfkzPN2wmgwFQ1D7e)}
\maketitle
Let $ u1\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k6\_ff\_siec : {\iota}$ be given.
Let $ k1\_xboole\_0 : {\iota}$ be given.
Let $ u4\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_net\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k2\_ff\_siec : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_ff\_siec : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (u1\_struct\_0~(k2\_ff\_siec~X0)=X0){\unicdcdcdhd}((u4\_struct\_0~(\\
k2\_ff\_siec~X0)=k1\_xboole\_0){\unicdcdcdhd}(k1\_net\_1~(k2\_ff\_siec~X0)=k1\_xboole\_0))\end{array}
\label{hyp:ehcdpfggggpfdhjgfgdg}
\end{equation}
Assume the following.
\begin{equation}
{{k6\_ff\_siec}={{{k1\_ff\_siec}~{k1\_xboole\_0}}~{k1\_xboole\_0}}}\label{hyp:eggdpfggggpfdhjgfgdg}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{{k2\_ff\_siec}~{X0}}={{{k1\_ff\_siec}~{X0}}~{k1\_xboole\_0}}}}\label{hyp:egcdpfggggpfdhjgfgdg}
\end{equation}
\begin{theorem}\label{thm:ehgdpfggggpfdhjgfgdg}
$$\begin{array}{c}(u1\_struct\_0~k6\_ff\_siec=k1\_xboole\_0){\unicdcdcdhd}((u4\_struct\_0~k6\_ff\_siec=\\
k1\_xboole\_0){\unicdcdcdhd}(k1\_net\_1~k6\_ff\_siec=k1\_xboole\_0))\end{array}$$
\end{theorem}
\end{document}
