\documentclass{article}
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\newtheorem{lemma}{Lemma}
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\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
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\begin{document}
\title{t6\_polyeq\_1 (TMMgQ1TGVqfkf5jBmyYyFU6wjcCb3NAwwRu)}
\maketitle
Let $ v1\_xcmplx\_0 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k1\_quin\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}$ be given.
Let $ k6\_numbers : {\iota}$ be given.
Let $ k3\_polyeq\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}}$ be given.
Let $ k4\_xcmplx\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k7\_xcmplx\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k3\_xcmplx\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ k2\_xcmplx\_0 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k3\_square\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v1\_xcmplx\_0~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (v1\_xcmplx\_0~X1){\unicdbdjdcd}({\unicdcdadad} X2 .  \\
(v1\_xcmplx\_0~X2){\unicdbdjdcd}({\unicdcdadad} X3 .  (v1\_xcmplx\_0~X3){\unicdbdjdcd}(((k1\_quin\_1~\\
X0~X1~X2=k6\_numbers){\unicdcdcdhd}(k2\_xcmplx\_0~(k2\_xcmplx\_0~(k3\_xcmplx\_0~\\
X0~(k3\_square\_1~X3))~(k3\_xcmplx\_0~X1~X3))~X2=k6\_numbers)){\unicdbdjdcd}((X0=\\
k6\_numbers){\unicdcdcdid}(X3=k4\_xcmplx\_0~(k7\_xcmplx\_0~X1~(k3\_xcmplx\_0~np\_\_2~\\
X0))))))))\end{array}
\label{hyp:ehcdadpfbhfhjgogpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v1\_xcmplx\_0~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (v1\_xcmplx\_0~X1){\unicdbdjdcd}({\unicdcdadad} X2 .  \\
(v1\_xcmplx\_0~X2){\unicdbdjdcd}({\unicdcdadad} X3 .  (v1\_xcmplx\_0~X3){\unicdbdjdcd}(k3\_polyeq\_1~\\
X0~X1~X2~X3=k2\_xcmplx\_0~(k2\_xcmplx\_0~(k3\_xcmplx\_0~X0~(k3\_square\_1~\\
X3))~(k3\_xcmplx\_0~X1~X3))~X2))))\end{array}
\label{hyp:egcdpfahpgmgjhfgbhpfbd}
\end{equation}
\begin{theorem}\label{thm:ehgdpfahpgmgjhfgbhpfbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (v1\_xcmplx\_0~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (v1\_xcmplx\_0~X1){\unicdbdjdcd}({\unicdcdadad} X2 .  \\
(v1\_xcmplx\_0~X2){\unicdbdjdcd}({\unicdcdadad} X3 .  (v1\_xcmplx\_0~X3){\unicdbdjdcd}(((k1\_quin\_1~\\
X0~X1~X2=k6\_numbers){\unicdcdcdhd}(k3\_polyeq\_1~X0~X1~X2~X3=k6\_numbers)){\unicdbdjdcd}((\\
X0=k6\_numbers){\unicdcdcdid}(X3=k4\_xcmplx\_0~(k7\_xcmplx\_0~X1~(k3\_xcmplx\_0~\\
np\_\_2~X0))))))))\end{array}$$
\end{theorem}
\end{document}
