\documentclass{article}
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\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
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\newcommand\preoh[1]{\lnot #1}
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\begin{document}
\title{t74\_zf\_lang (TMF1Gdwrfc2nXb2LaQ1EZMjr3izR3Dp7DTr)}
\maketitle
Let $ v1\_zf\_lang : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ m2\_finseq\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k5\_numbers : {\iota}$ be given.
Let $ v5\_zf\_lang : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ r3\_zf\_lang : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k21\_zf\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k22\_zf\_lang : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ r1\_zf\_lang : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k7\_zf\_lang : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k4\_ordinal1 : {\iota}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}({\unicdcdadad} X1 .  \\
((v1\_zf\_lang~X1){\unicdcdcdhd}(m2\_finseq\_1~X1~k5\_numbers)){\unicdbdjdcd}((r1\_zf\_lang~\\
X0~X1){\unicdbdjdcd}(r3\_zf\_lang~X0~X1)))\end{array}
\label{hyp:ehgdbdpfkhggpfmgbgoghg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}({\unicdcdadad} X1 .  \\
((v1\_zf\_lang~X1){\unicdcdcdhd}(m2\_finseq\_1~X1~k5\_numbers)){\unicdbdjdcd}((v5\_zf\_lang~\\
X0){\unicdbdjdcd}((r1\_zf\_lang~X1~X0){\unicdbdjded}((X1=k21\_zf\_lang~X0){\unicdcdcdid}(X1=k22\_zf\_lang~\\
X0)))))\end{array}
\label{hyp:ehfdhdpfkhggpfmgbgoghg}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}({\unicdcdadad} X1 .  \\
((v1\_zf\_lang~X1){\unicdcdcdhd}(m2\_finseq\_1~X1~k5\_numbers)){\unicdbdjdcd}((v5\_zf\_lang~\\
X0){\unicdbdjdcd}((\preoh (X1=k21\_zf\_lang~X0){\unicdcdcdhd}({\unicdcdadad} X2 .  ((v1\_zf\_lang~X2){\unicdcdcdhd}(m2\_finseq\_1~\\
X2~k5\_numbers)){\unicdbdjdcd}(k7\_zf\_lang~X1~X2{\unicdcdgdad}X0))){\unicdcdcdhd}((({\unicdcdaddd} X2 .  ((v1\_zf\_lang~\\
X2){\unicdcdcdhd}(m2\_finseq\_1~X2~k5\_numbers)){\unicdcdcdhd}(k7\_zf\_lang~X1~X2=X0)){\unicdbdjdcd}(X1=\\
k21\_zf\_lang~X0)){\unicdcdcdhd}((\preoh (X1=k22\_zf\_lang~X0){\unicdcdcdhd}({\unicdcdadad} X2 .  ((v1\_zf\_lang~\\
X2){\unicdcdcdhd}(m2\_finseq\_1~X2~k5\_numbers)){\unicdbdjdcd}(k7\_zf\_lang~X2~X1{\unicdcdgdad}X0))){\unicdcdcdhd}((\\
{\unicdcdaddd} X2 .  ((v1\_zf\_lang~X2){\unicdcdcdhd}(m2\_finseq\_1~X2~k5\_numbers)){\unicdcdcdhd}(k7\_zf\_lang~\\
X2~X1=X0)){\unicdbdjdcd}(X1=k22\_zf\_lang~X0)))))))\end{array}
\label{hyp:ehddidpfkhggpfmgbgoghg}
\end{equation}
Assume the following.
\begin{equation}
{{k5\_numbers}={k4\_ordinal1}}\label{hyp:chfgegfgggjgogjgehjgpgogpflgfdpfogfhngcgfgchdh}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}((\\
v5\_zf\_lang~X0){\unicdbdjded}({\unicdcdaddd} X1 .  ((v1\_zf\_lang~X1){\unicdcdcdhd}(m2\_finseq\_1~X1~\\
k5\_numbers)){\unicdcdcdhd}({\unicdcdaddd} X2 .  ((v1\_zf\_lang~X2){\unicdcdcdhd}(m2\_finseq\_1~X2~k5\_numbers)){\unicdcdcdhd}\\
(X0=k7\_zf\_lang~X1~X2))))\end{array}
\label{hyp:egbdddpfkhggpfmgbgoghg}
\end{equation}
\begin{theorem}\label{thm:ehhdedpfkhggpfmgbgoghg}
$$\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_zf\_lang~X0){\unicdcdcdhd}(m2\_finseq\_1~X0~k5\_numbers)){\unicdbdjdcd}((\\
v5\_zf\_lang~X0){\unicdbdjdcd}((r3\_zf\_lang~(k21\_zf\_lang~X0)~X0){\unicdcdcdhd}(r3\_zf\_lang~\\
(k22\_zf\_lang~X0)~X0)))\end{array}$$
\end{theorem}
\end{document}
