\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t78\_cohsp\_1 (TMXynNXhwDiLsZERQTCyNcoKfZzKEEeYb54)}
\maketitle
Let $ r1\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k14\_cohsp\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k4\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ k1\_xtuple\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k2\_xtuple\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  (k4\_tarski~X2~np\_\_2 \in k14\_cohsp\_1~\\
X0~X1){\unicdbdjded}(X2 \in X1)\end{array}
\label{hyp:ehhdhdpfdgpgigdhahpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  (k4\_tarski~X2~np\_\_1 \in k14\_cohsp\_1~\\
X0~X1){\unicdbdjded}(X2 \in X0)\end{array}
\label{hyp:ehhdgdpfdgpgigdhahpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  (X2 \in k14\_cohsp\_1~X0~X1){\unicdbdjdcd}((X2=\\
k4\_tarski~(k1\_xtuple\_0~X2)~(k2\_xtuple\_0~X2)){\unicdcdcdhd}(((k2\_xtuple\_0~\\
X2=np\_\_1){\unicdcdcdhd}(k1\_xtuple\_0~X2 \in X0)){\unicdcdcdid}((k2\_xtuple\_0~X2=np\_\_2){\unicdcdcdhd}(k1\_xtuple\_0~\\
X2 \in X1))))\end{array}
\label{hyp:ehhdfdpfdgpgigdhahpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (r1\_tarski~X0~X1){\unicdbdjded}({\unicdcdadad} X2 .  (X2 \in X0){\unicdbdjdcd}\\
(X2 \in X1))\end{array}
\label{hyp:egddpfehbgchdhlgjg}
\end{equation}
\begin{theorem}\label{thm:ehhdidpfdgpgigdhahpfbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  {\unicdcdadad} X3 .  (r1\_tarski~(k14\_cohsp\_1~\\
X0~X1)~(k14\_cohsp\_1~X2~X3)){\unicdbdjded}((r1\_tarski~X0~X2){\unicdcdcdhd}(r1\_tarski~X1~X3))\end{array}$$
\end{theorem}
\end{document}
