\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t7\_e\_siec (TMU6nHCmjAGLXkjc6DPPHNNaPpyq8yeUguH)}
\maketitle
Let $ u1\_struct\_0 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k3\_e\_siec : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ u1\_e\_siec : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_xboole\_0 : {\iota}$ be given.
Let $ u2\_e\_siec : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ v1\_relat\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ g1\_e\_siec : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}$ be given.
Let $ v1\_xboole\_0 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v1\_e\_siec : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v2\_e\_siec : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v3\_e\_siec : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ l1\_e\_siec : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  ((v1\_relat\_1~X1){\unicdcdcdhd}(v1\_relat\_1~\\
X2)){\unicdbdjdcd}({\unicdcdadad} X3 .  {\unicdcdadad} X4 .  {\unicdcdadad} X5 .  (g1\_e\_siec~X0~X1~X2=g1\_e\_siec~\\
X3~X4~X5){\unicdbdjdcd}((X0=X3){\unicdcdcdhd}((X1=X4){\unicdcdcdhd}(X2=X5))))\end{array}
\label{hyp:ggchfgfgpfhgbdpffgpfdhjgfgdg}
\end{equation}
Assume the following.
\begin{equation}
{{v1\_xboole\_0}~{k1\_xboole\_0}}\label{hyp:ggdgbdpfihcgpgpgmgfgpfad}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v1\_e\_siec~(k3\_e\_siec~X0)){\unicdcdcdhd}((v2\_e\_siec~(k3\_e\_siec~\\
X0)){\unicdcdcdhd}((v3\_e\_siec~(k3\_e\_siec~X0)){\unicdcdcdhd}(l1\_e\_siec~(k3\_e\_siec~X0))))\end{array}
\label{hyp:egehpflgddpffgpfdhjgfgdg}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{{k3\_e\_siec}~{X0}}={{{{g1\_e\_siec}~{X0}}~{k1\_xboole\_0}}~{k1\_xboole\_0}}}}\label{hyp:egfdpffgpfdhjgfgdg}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{({{v1\_xboole\_0}~{X0}})}{\unicdbdjdcd}{({{v1\_relat\_1}~{X0}})}}}\label{hyp:dgdgbdpfchfgmgbgehpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (l1\_e\_siec~X0){\unicdbdjdcd}((v1\_e\_siec~X0){\unicdbdjdcd}(X0=g1\_e\_siec~(u1\_struct\_0~\\
X0)~(u1\_e\_siec~X0)~(u2\_e\_siec~X0)))\end{array}
\label{hyp:bgcgdhehchbgdgehogfgdhdhpfghbdpffgpfdhjgfgdg}
\end{equation}
\begin{theorem}\label{thm:ehhdpffgpfdhjgfgdg}
$$\begin{array}{c}{\unicdcdadad} X0 .  (u1\_struct\_0~(k3\_e\_siec~X0)=X0){\unicdcdcdhd}((u1\_e\_siec~(k3\_e\_siec~\\
X0)=k1\_xboole\_0){\unicdcdcdhd}(u2\_e\_siec~(k3\_e\_siec~X0)=k1\_xboole\_0))\end{array}$$
\end{theorem}
\end{document}
