\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t84\_afinsq\_1 (TMbkH3Pdtuuhtz5hAuCNLZ5Qb3uE3NHUfFN)}
\maketitle
Let $ k1\_afinsq\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k16\_afinsq\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}}$ be given.
Let $ np\_\_4 : {\iota}$ be given.
Let $ v1\_relat\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v5\_ordinal1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v1\_funct\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ v1\_finset\_1 : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k1\_ordinal4 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k5\_afinsq\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k1\_funct\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k6\_numbers : {\iota}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ np\_\_2 : {\iota}$ be given.
Let $ np\_\_3 : {\iota}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  ((v1\_relat\_1~X0){\unicdcdcdhd}((v5\_ordinal1~X0){\unicdcdcdhd}((v1\_funct\_1~\\
X0){\unicdcdcdhd}(v1\_finset\_1~X0)))){\unicdbdjdcd}({\unicdcdadad} X1 .  {\unicdcdadad} X2 .  {\unicdcdadad} X3 .  {\unicdcdadad} X4 .  \\
(X0=k1\_ordinal4~(k1\_ordinal4~(k1\_ordinal4~(k5\_afinsq\_1~X1)~(\\
k5\_afinsq\_1~X2))~(k5\_afinsq\_1~X3))~(k5\_afinsq\_1~X4)){\unicdbdjdcd}((k1\_afinsq\_1~\\
X0=np\_\_4){\unicdcdcdhd}((k1\_funct\_1~X0~k6\_numbers=X1){\unicdcdcdhd}((k1\_funct\_1~X0~np\_\_1=\\
X2){\unicdcdcdhd}((k1\_funct\_1~X0~np\_\_2=X3){\unicdcdcdhd}(k1\_funct\_1~X0~np\_\_3=X4))))))\end{array}
\label{hyp:ehedfdpfbgggjgogdhbhpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  {\unicdcdadad} X3 .  (v5\_ordinal1~(k16\_afinsq\_1~\\
X0~X1~X2~X3)){\unicdcdcdhd}(v1\_finset\_1~(k16\_afinsq\_1~X0~X1~X2~X3))\end{array}
\label{hyp:ggdgcdhdpfbgggjgogdhbhpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  {\unicdcdadad} X3 .  (v1\_relat\_1~(k16\_afinsq\_1~\\
X0~X1~X2~X3)){\unicdcdcdhd}(v1\_funct\_1~(k16\_afinsq\_1~X0~X1~X2~X3))\end{array}
\label{hyp:ggdgcdgdpfbgggjgogdhbhpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  {\unicdcdadad} X3 .  k16\_afinsq\_1~X0~X1~\\
X2~X3=k1\_ordinal4~(k1\_ordinal4~(k1\_ordinal4~(k5\_afinsq\_1~X0)~\\
(k5\_afinsq\_1~X1))~(k5\_afinsq\_1~X2))~(k5\_afinsq\_1~X3)\end{array}
\label{hyp:egbdedpfbgggjgogdhbhpfbd}
\end{equation}
\begin{theorem}\label{thm:ehidedpfbgggjgogdhbhpfbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  {\unicdcdadad} X2 .  {\unicdcdadad} X3 .  k1\_afinsq\_1~(k16\_afinsq\_1~\\
X0~X1~X2~X3)=np\_\_4\end{array}$$
\end{theorem}
\end{document}
